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Lady bird [3.3K]
4 years ago
14

Why does icing sugar dissolve more rapidly than granular sugar?

Physics
1 answer:
kogti [31]4 years ago
3 0
Icing sugar has a larger surface area meaning smaller particles allowing it to dissolve faster
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The average speed of a car being driven in London is 11 miles per hour. If you have to drive 15 miles from your home to work in
arlik [135]
It would take you approximately  an hour and 15 mins
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3 years ago
Here is a graph of speed vs time. If the object is moving to the east, which BEST describes the speed and velocity of the graph?
san4es73 [151]

Answer: A JUST DID IT ON USA TESTPREP

Explanation:

5 0
3 years ago
The following voltage drops are measured across three resistors in series: 5.5 V. 8.2 V. and 12,3 V. What is the value of the so
DiKsa [7]

Answer:

26 V

Explanation:

Given:

The three resistors 5.5 V. 8.2 V. and 12,3 V. are connected in series.

Now we have to find out the source voltage  to which these resistors arc connected ?

Solution:

As we know in series the magnitude of current is uniform but the voltage divides between the resistors supplied from source voltage.So the magnitude of source voltage is, 5.5 V + 8.2 V + 12.3 V = 26 V

Hence, the value of the source voltage to which these resistors are connected is  26 V

7 0
3 years ago
A 10kg wagon is pulled along the floor with a force of 5N to the North.
77julia77 [94]

Answer:

50N

Explanation:

4 0
2 years ago
How long will it take a 2.3"x10^3 kg truck to go from 22.2 m/s to a complete stop if acted on by a force of -1.26x10^4 N.What wo
Greeley [361]

The stopping distance is 45.0 m

Explanation:

First of all, we find the acceleration of the truck, by using Newton's second law:

F=ma

where

F=-1.26\cdot 10^4 N is the net force on the truck

m=2.3\cdot 10^3 kg is the mass of the truck

a is its acceleration

Solving for a,

a=\frac{F}{m}=\frac{-1.26\cdot 10^4}{2.3\cdot 10^3}=-5.48 m/s^2

where the negative sign means the acceleration is opposite to the direction of motion.

Now, since the motion of the truck is at constant acceleration, we can apply the following suvat equation:

v^2-u^2=2as

where

v = 0 is the final velocity of the truck

u = 22.2 m/s is the initial velocity

a=-5.48 m/s^2 is the acceleration

s is the stopping distance

And solving for s,

s=\frac{v^2-u^2}{2a}=\frac{0-(22.2)^2}{2(-5.48)}=45.0 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0
4 years ago
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