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o-na [289]
2 years ago
8

How many atoms of carbon2C4H10 + 13O2 → 8CO2 + 10H2O have?

Chemistry
1 answer:
adelina 88 [10]2 years ago
5 0
8 Atoms of Carbon on both sides.Hope this helps

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Consider the following reversible reaction.
andriy [413]

Answer:

No one is correct. The correct expression is:

Keq = [H₂]²  . [O₂]² / [H₂O]²

Explanation:

To build the Keq expression in a chemical equilibrium you must consider the molar concentrations of reactants / products, and they must be elevated to the stoichiometric coefficient.

The balance reaction is:

<u>2</u> H₂O (g)  ⇄  <u>2</u> H₂ (g)  +  O₂ (g)

Keq = [H₂]²  . [O₂]  / [H₂O]²

In opposite side: <u>2</u> H₂ (g)  +  O₂ (g)   ⇄  <u>2</u> H₂O (g)

Keq =  [H₂O]² / [H₂]²  . [O₂]  

6 0
3 years ago
What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi
insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

          E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}

                             = 0.535 - 1.065

                             = - 0.53 V

Also, it is known that relation between E^{o}_{cell} and K is as follows.

            E^{o}_{cell} = \frac{RT}{nF} \times ln K

                 ln K = \frac{nFE^{0}_{cell}}{RT}      

Substituting the given values into the above formula as follows.

                 ln K = \frac{nFE^{0}_{cell}}{RT}    

                        =  \frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}  

                ln K = -41.28

                    K = e^{-41.28}    

                        = 1 \times 10^{-18}

Thus, we can conclude that the value of the equilibrium constant for the given reaction is 1 \times 10^{-18}.      

5 0
3 years ago
What is the total number of atoms in this formula?<br> NaHCO3
Pavel [41]
6 - one sodium atom, 1 hydrogen atom, 1 carbon atom, and 3 oxygen atoms.


7 0
3 years ago
Lava that cools quickly forms: A. basalt B. granite C.quartz D. none the above
lawyer [7]
The answer is A I’m pretty sure lol
3 0
2 years ago
Read 2 more answers
During the processes of erosion and deposition, sediments that are the ________ in size will be carried the greatest distances b
Ahat [919]

The full sentences are given below:

1. During the process of erosion and deposition, sediments that are the SMALLEST in size will be carried the greatest distance before being deposited.

Erosion and deposition are the methods by which sand and rock particles are moved from one place to another. The erosion can be caused by water or wind. Water and wind have the capacity to transport particle from one location and deposit them in another location. How far the erosion is able to move the particles depend on the weight of the particles. It is easier for erosion to carry small particles over a long distance than for it to carry large particles over the same distance.

2. Most METAMORPHIC rocks form under conditions found a few kilometer under the earth surface.

Metamorphic rocks generally are formed from existing rocks. The existing rocks are usually subjected to heat and pressure, which cause radical changes in the chemical and physical properties of the rock. Metamorphic rocks can be formed underneath the earth surface if they are subjected to high temperature and pressure by the rock layers above them.

3 0
3 years ago
Read 2 more answers
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