Answer:
well the world would be shocked
Explanation:
and suprise
<u>Given:</u>
Mass of solvent water = 4.50 kg
Freezing point of the solution = -11 C
Freezing point depression constant = 1.86 C/m
<u>To determine:</u>
Moles of methanol to be added
<u>Explanation:</u>
The freezing point depression ΔTf is related to the molality m through the constant kf, as follows:
ΔTf = kf*m
where ΔTf = Freezing point of pure solvent (water) - Freezing pt of solution
ΔTf = 0 C - (-11.0 C) = 11.0 C
m = molality = moles of methanol/kg of water = moles of methanol/4.50 kg
11.0 = 1.86 * moles of methanol/4.50
moles of methanol = 26.613 moles
Ans: Thus around 26.6 moles of methanol should be added to 4.50 kg of water.
Answer:
Distance: 16m Displacement: 8m North
Explanation:
Total distance is the total amount traveled, regardless of direction. So, you would just add 12 and 4 to get a total distance of 16m. Displacement is the distance/direction from the start to the end point, regardless of which way you got there. So, to find displacement, you just subtract:
12m North - 4m South = 8m North
** I could be wrong so definitely double check this answer with a similar question**
Answer:
Explanation:
2HCl = H₂ + Cl₂
2 mole 1 mole 1 mole
73 gram HCl = 73 / 36.5 = 2 mole of HCl
2 moles of HCl will produce 1 mole of chlorine gas .
At STP , one mole of chlorine gas has volume equal to 22.4 litre .
