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n200080 [17]
3 years ago
13

A gas has a pressure of 4.62 atm when its volume is 2.33 l. what will be the pressure in torr when the volume is changed to 1.03

l?
Chemistry
1 answer:
denis23 [38]3 years ago
6 0
We know that the pressure, volume and temperature keeps a relations as follows: 
P*V/T = constant  
If we consider that the temperature keeps the same value from state 1 to state 2, then we have: 
P1*V1 = P2*V2  
4.62*2.33 = P2*1.03  
Then P2 = 10.45 atm  
Finally we know that 1 atm is 760 torr, so then the final pressure will be: 
P2 = 10.45 * 760 = 7942 torr
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If 4.00 g of NaCl react with 10.00 g of AgNO3, what is the excess reactant?
Mekhanik [1.2K]
The reaction formula of this is NaCl + AgNO3 = NaNO3 + AgCl. The mole number of NaCl is 4/58.5=0.068 mol. The mole number of AgNO3 is 10/170=0.059 mol. So the NaCl is excess.
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3 years ago
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5. What is the volume of 10 moles of a gas at 300 K held at a pressure of 3.5 atm?
Helga [31]

70.33 L  is the volume of 10 moles of a gas at 300 K held at a pressure of 3.5 atm.

<h3>What is volume?</h3>

Volume is the percentage of a liquid, solid, or gas's three-dimensional space that it occupies.

Liters, cubic metres, gallons, millilitres, teaspoons, and ounces are some of the more popular units used to express volume, though there are many others.

We will use ideal gas law to find the volume

PV = nRT

Can also be written as

V = (nRT)/P

Where,

P = pressure

V = volume

n = amount of substance

R = ideal gas constant

T = temperature

Here, we have given

P = 3.5 atm

V = to find

n = 10 moles

R = 0.08206 L⋅atm/K⋅mol

T = 300k

Lets substitute the values

V = (10 × 0.08206 × 300)/3.5

V =  70.33 L

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3 0
1 year ago
Which is the state of matter shown in this figure ?
Veronika [31]

Answer:

Solid

Explanation:

The particles are densely packed and in a defined shape, therefore they would be defined as a solid.

5 0
3 years ago
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calculate the (m/v) of nacl of a solution made by diluting 25.0 ml of a 7.50 (m/v)% NaCl solution to a total volume of 75.00 ml
postnew [5]

Answer:

c

Explanation:

8 0
2 years ago
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A solution contains 0.115 mol h2o and an unknown number of moles of nacl. the vapor pressure of the solution at 30°c is 25.7 tor
Valentin [98]
According to Raoult's low:
We will use this formula: Vp(Solution) = mole fraction of solvent * Vp(solvent)
∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr 
So by substitution:
∴ mole fraction of solvent = 25.7 / 31.8 =0.808 
when we assume the moles of solute NaCl = X 
and according to the mole fraction of solvent formula:
mole fraction of solvent = moles of solvent / (moles of solvent + moles of solute)
by substitute:
∴ 0.808 = 0.115 / (0.115 + X)
 So X (the no.of moles of NaCl) = 0.027 m
8 0
3 years ago
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