Question

Select the correct answer from each drop-down menu.

Answer 1

Answer:

Correlation coefficient ≈ 0.9445

This indicates that the weight of a student increases as the height of the student increases.

Step-by-step explanation:

Answer 2

Answer:

Correlation coefficient ≈ 0.9445

This indicates that the weight of a student increases as the height of the student increases.

Step-by-step explanation:

The rest of the question is the following table

value of x (height) are        58, 59,   60,  62,  63,  64,   66,  68,  70

Value of y (weight) are:      122, 128, 126, 133, 145, 136, 144, 150, 151

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To calculate the correlation coefficient we will use the following form:

$r = \frac{n(\sum xy)- (\sum x)(\sum y)}{\sqrt{n\sum x^2 - (\sum x)^2} \sqrt{n\sum y^2-(\sum y)^2} }$

So, n (the number of terms) = 9

∑x = 570, ∑y= 1236, ∑ x²= 36234, ∑ y²= 170694 and ∑xy=78617

So, the correlation coefficient =

$r = \frac{9\times 78617- 570\times 1236}{\sqrt{9\times 36234-(570)^2}\sqrt{9\times 170694-(1236)^2}}$

∴ r =  0.9445

So, weight of a student increases as the height of the student increases.