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miv72 [106K]
3 years ago
10

Describe a situation when you might travel at a high velocity, but with low acceleration

Physics
1 answer:
Alisiya [41]3 years ago
5 0

Reading a book in your warm, comfy seat ... in Row-27 of a
passenger airliner cruising at 450 miles per hour.
 
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Four charges of magnitude +q are placed at the corners of a square whose sides have a length d. What is the magnitude of the tot
guapka [62]

Answer:

F = \frac{4kqQb}{(b^2 + \frac{d^2}{2})^{1.5}}

Explanation:

Since all the four charges are equidistant from the position of Q

so here we can assume this charge distribution to be uniform same as that of a ring

so here electric field due to ring on its axis is given as

E = \frac{k(4q)x}{(x^2 + R^2)^{1.5}}

here we have

x = b

and the radius of equivalent ring is given as the distance of each corner to the center of square

R = \frac{d}{\sqrt2}

now we have

E = \frac{4kq b}{(b^2 + \frac{d^2}{2})^{1.5}}

so the force on the charge is given as

F = QE

F = \frac{4kqQb}{(b^2 + \frac{d^2}{2})^{1.5}}

3 0
3 years ago
The electric field 2.5 mm from a uniform sheet of charge is σ=800, NC. How much charge is contained in a 5.0x5.0 cm section of t
slamgirl [31]

Answer:

The charge is 2.75\times10^{-13}\ C

Explanation:

Given that,

Distance = 2.5 mm

Electric field = 800 NC

Length L=5.0\times5.0\times10^{-4}\ m

We need to calculate the linear charge density

Using formula of linear charge density

E=\dfrac{2k\lambda}{r}

\lambda=\dfrac{Er}{2k}

Put the value into the formula

\lambda=\dfrac{800\times2.5\times10^{-3}}{2\times9\times10^{9}}

\lambda=1.1\times10^{-10}\ C/m

We need to calculate the charge

Using formula of charge

Q=\lambda\timesL

Put the value into the formula

Q=1.1\times10^{-10}\times(5.0\times5.0\times10^{-4})

Q=2.75\times10^{-13}\ C

Hence, The charge is 2.75\times10^{-13}\ C

5 0
3 years ago
After Moseley's discovery in 1913, the periodic law stated that physical and chemical properties tend to repeat periodically whe
stich3 [128]

Answer:

Option B

Explanation:

The correct answer is Option B.

Before Moseley's discovery in 1913, In Mendeleev's periodic table the elements rearranged with increasing atomic mass.

Mendeleev was not able to locate hydrogen atom and late isotopes found violate Mendeleev table. The biggest drawback was that the atomic mass was not regular when moving one element to another.

But Moseley's arranged element in the periodic table with increasing atomic number.  

3 0
3 years ago
An asteroid orbits the Sun every 176 years. What is the asteroids average distance from the Sun? P ^ 2 = a ^ 3 where p = period
KatRina [158]

Answer:

The value is  x =  45.99 \  Au

Explanation:

From the question we are told that

   The period of the  asteroid is   T =  176 \ years = 176 * 365 * 24 * 60* 60 = 5.55*10^{9}\ s

Generally the average distance of the asteroid from the sun is mathematically represented as

            R = \sqrt[3]{ \frac{G M * T^2 }{4 \pi} }

Here M is the mass of the sun with a value  

        M  =  1.99*10^{30} \  kg

         G  is the gravitational constant with value  G  =  6.67 *10^{-11}  \  m^3 \cdot kg^{-1} \cdot  s^{-2}

           R = \sqrt[3]{ \frac{6.67 *10^{-11}  * 1.99*10^{30} * [5.55 *10^{9}]^2 }{4 * 3.142 } }

=>       R = 6.88 *10^{12} \  m

Generally

         1.496* 10^{11}  \  m  \to  1 Au (Astronomical \  unit )

So

          R = 6.88 *10^{12} \  m \ \ \ \ \to \ \   x \  Au

=>      x =  \frac{6.88 *10^{12}}{1.496 *10^{11}}

=>       x =  45.99 \  Au

       

7 0
2 years ago
Psychophysics is a discipline in psychology that focuses solely on the identification of stimuli. T F
Rzqust [24]
Hi There,

  
This is False.
Hope this helped!
3 0
3 years ago
Read 2 more answers
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