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Rasek [7]
3 years ago
14

if pes represents the potential energy stored in a spring in kg•m^2/s^2 and x represents the change in the springs length from i

ts equilibrium position im m what is the unit for the spring constant k in the formula PEs=1/2kx^2
Physics
1 answer:
musickatia [10]3 years ago
8 0
Unit for x - the change in the spring length:
x = [ m ]
PE s =  1/2 k x²
[ kg m² / s² ] = 1/2 k * [ m² ]   /: m²
k = [ kg / s² ]
Answer: The unit for spring constant k is kg/ s²
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Answer:

2.67kg

Explanation:

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v_{max}=\omega A............(1)

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where k is the force constant of the spring and m is the loaded mass.

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We then combine equations (2) and (3) as follows;

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According to the problem, the following  are given;

v_ {max }=1.92m/s\\A=0.21m\\k=223N/m

We then substitute these values into equation (4) and solve for the unknown mass m as follows;

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3 years ago
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