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Charra [1.4K]
3 years ago
6

At an outdoor market, a bunch of bananas is set on a spring scale to measure the weight. The spring sets the full bunch of banan

as into vertical oscillatory motion, which is harmonic with an amplitude 0.21 m. The maximum speed of the bananas is observed to be 1.92 m/s. What is the mass of the bananas? The spring of the scale has a force constant 223 N/m. Answer in units of kg.
Physics
1 answer:
Elina [12.6K]3 years ago
8 0

Answer:

2.67kg

Explanation:

The maximum velocity, v _ {max} of a body experiencing simple harmonic motion is given by equation (1);

v_{max}=\omega A............(1)

where \omega is the angular velocity and A is the amplitude.

The problem describes the oscillation of a loaded spring, and for a loaded spring the angular velocity is given by equation (2);

\omega=\sqrt{\frac{k}{m}}.................(2)

where k is the force constant of the spring and m is the loaded mass.

We can make \omega the subject of formula in equation (1) as follows;

\omega=\frac{v_{max}}{A}.................(3)

We then combine equations (2) and (3) as follows;

\frac{v_{max}}{A}=\sqrt{\frac{k}{m}}.................(4)

According to the problem, the following  are given;

v_ {max }=1.92m/s\\A=0.21m\\k=223N/m

We then substitute these values into equation (4) and solve for the unknown mass m as follows;

\frac{1.92}{0.21}=\sqrt{\frac{223}{m}}

9.143=\sqrt{\frac{223}{m}}

Squaring both sides, we obtain the following;

9.143^2=\frac{223}{m}\\9.143^2*m=223\\83.592m=223\\therefore\\m=\frac{223}{83.592}\\m=2.67kg

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JulsSmile [24]

Explanation:

V=u+at

where,

v=final speed

u=initial speed,(starting speed)

a=acceleration

t=time

  1. v=u+at = 6=2+a*2

6=2+2a

2a=6-2

2a=4

a=4/2 = 2

a =2

2. to find time taken

v=u+at

25=5*2t

2t=25-5

2t=20

t=20/2

t=10sec

3. finding final speed

v=u+at

v=4+10*2

=4+20

v=24m/sec

5.v=u+at

=5+8*10

=5+80

V=85m/sev

6. v=u+at

8=u+4*2

8=u+8

U=8/8

u=1

these are your missing values

5 0
3 years ago
CHUULILULILUUU
igor_vitrenko [27]

Answer:

31 I think.

Explanation:

3 0
3 years ago
Compare and Contrast How is a tug - of - war similar to unequal sharing of electron
laiz [17]
Imagine that the two atoms are playing tug of war with the electron, but one is pulling with a stronger force than the other. This inequality results in the majority of the rope being pulled toward the stronger atom. In the bond, the electron is pulled closer to the stronger atom too. This results in each side having a partial charge, one being more negative than the other.
7 0
3 years ago
what is the capacitance of two square parallel plates 6.7 cm on a side that are separated by 1.8 mm of paraffin? the dielectric
almond37 [142]

The capacitance of two square parallel plates will be 1.777 farads.

<h3>What is the capacitance of two parallel plates?</h3>

The body's capacity to hold electric charge is constrained by capacitance. There is a capacitance for each capacitor. Two metallic sheets of area A, spaced by d, make up the standard parallel-plate capacitor.

The parallel plate capacitor formula is given by:

C = ε Ad

Two square parallel plates 6.7 cm on a side are separated by 1.8 mm of paraffin. The dielectric constant of paraffin is 2.2. Then the capacitance of two square parallel plates will be given as,

C = ε Ad

C = 2.2 x 0.67 x 0.67 x 1.8

C = 1.777 farad

Two parallel square plates will have a capacitance of 1.777 farads.

More about the capacitance of two parallel plates link is given below.

brainly.com/question/12733413

#SPJ4

7 0
2 years ago
A truck is speeding up as it travels on an interstate. The truck's momentum (in kg · m/s) is proportional to the truck's speed (
serious [3.7K]

Answer:

a)48300 times

b)P = 821100  kg · m/s

Explanation:

Given that

m = 48300 kg

v= 23 m/s

We know that linear momentum (P) given as

P = m v

P = 48300 x 23  kg · m/s

So we can say that truck momentum is 48300 times its velocity.

Now given that

v= 17 m/s

P = m v

P = 48300 x 17  kg · m/s

P = 821100  kg · m/s

6 0
4 years ago
Read 2 more answers
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