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zzz [600]
3 years ago
10

Plssss answerrrrr hurry

Chemistry
2 answers:
taurus [48]3 years ago
5 0

Answer:

Incomplete = pink

Complete = Green

Explanation:

emmasim [6.3K]3 years ago
4 0

Answer:

I dont know

Explanation:

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What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
Sidana [21]

Answer:

0.50 M

Explanation:

Given data

  • Mass of sodium sulfate (solute): 7.1 g
  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M

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Which of these is an example of biotic factor
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Biotic components, or biotic factors, can be described as any living component that affects another organism or shapes the ecosystem. This includes both animals that consume other organisms within their ecosystem, and the organism that is being consumed
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What would be the volume in liters of an 2.45 liter sample of gas at 594 °C
Ber [7]

Answer:

V_2= 1.19L

Explanation:

Hello there!

In this case, since the STP conditions are defined by 1 atm (101.3 kPa) and 273 K, it is possible for us to use the combined gas law for this problem as we are given variable pressure, temperature and volume:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

In such a way, solving for V2 as the final volume, we obtain:

V_2=\frac{P_1V_1T_2}{P_2T_1} =\frac{156kPa*2.45L*273.15K}{101.3kPa*(594+273)K}\\\\V_2= 1.19L

Regards!

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