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vesna_86 [32]
3 years ago
8

Complete each statement to identify the form of asexual reproduction.

Chemistry
2 answers:
Mrrafil [7]3 years ago
8 0

Spore formation is a form of asexual reproduction used by mushrooms and molds.

During  budding, the offspring grows from the body of the parent.

Fragmentation is a form of asexual reproduction that must be followed by regeneration.

Explanation:

Asexual reproduction is the type of reproduction where the gamete formation and fusion have no relevance or existence. It functions on the process of somatic cell division via mitosis and the offsprings are identical to their parents.

The spore formation occurs in fungi through sporangia, bursting open to shed spores, forming into a new young ones. Budding occurs out as an outgrowth of the parent and attains maturity and separates. Fragmentation is the process where the parents fall apart into pieces and regeneration follows.

slava [35]3 years ago
6 0

Answer:

Spore formation is a form of asexual reproduction used by mushrooms and molds.

During  budding, the offspring grows from the body of the parent.

Fragmentation is a form of asexual reproduction that must be followed by regeneration.

Explanation:

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vovikov84 [41]
<h3>Answer:</h3>

2 atoms

<h3>Explanation:</h3>
  • Compounds are substances that are formed when two or more elements chemically combine.
  • They are made up of molecules that contain different atoms from different elements.
  • For example, KCl is a compound that is made up of two atoms, one potassium atom and one chloride atom.
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3 0
3 years ago
Predict the mass of iron (III) sulfide produced when 3.0 g of iron filings react completely with 2.5 g of yellow sulfur solid, S
777dan777 [17]
1) Chemical equation

16Fe(s) + 3S8(s) ---> 8Fe2S3

2) Molar ratios:

16 mol Fe : 3 mole S8 : 8 mol Fe2S3

3) Convert masses in grams to number of moles

number of moles = mass in grams / molar mass

a) iron, Fe

mass = 3.0 g
atomic mass = 55.845 g/mol

=> number of moles of Fe = 3.0g / 55.845 g/mol = 0.0537 mol

b) Sulfur, S8

mass = 2.5 g
molar mass = 8*32.065 g/mol = 256.52 g/mol

=> number of moles of S8 = 2.5g / 256.52 g/mol = 0.009746 mol

4) Limiting reactant

Theoretical ratio                           actual ratio

16 mol Fe / 3 mol S8                 0.0537 mol Fe / 0.009746 mol S8

5.33                                               5.50

So, there is a little bit more Fe than the theoretical needed to react all the S8, which means the S8 is the limiting reactant.

5) Calculate the number of moles of iron (III) produced with 2.5 g (0.009746 moles) of S8

3moles S8 / 8 moles Fe2S3 = 0.009746 moles S8 / x

=> x = 0.009746 * 8 / 3 moles Fe2S3 = 0.026 moles Fe2S3

6) Convert 0.026 moles Fe2S3 into grams

mass in grams = number of moles * molar mass

molar mass of Fe2S3 = 207.9 g/mol

mass = 0.026 mol * 207.9 g/mol = 5.40 g

7) Answer: option D)




3 0
3 years ago
Read 2 more answers
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VMariaS [17]

Answer: Sodium chloride

Explanation:

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tatyana61 [14]
I think the answer is C. acidic
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