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3 years ago

Complete each statement to identify the form of asexual reproduction.

Chemistry

2 answers:

Mrrafil [7]3 years ago

8 0

Spore formation is a form of asexual reproduction used by mushrooms and molds.

During budding, the offspring grows from the body of the parent.

Fragmentation is a form of asexual reproduction that must be followed by regeneration.

Explanation:

Asexual reproduction is the type of reproduction where the gamete formation and fusion have no relevance or existence. It functions on the process of somatic cell division via mitosis and the offsprings are identical to their parents.

The spore formation occurs in fungi through sporangia, bursting open to shed spores, forming into a new young ones. Budding occurs out as an outgrowth of the parent and attains maturity and separates. Fragmentation is the process where the parents fall apart into pieces and regeneration follows.

slava [35]3 years ago

6 0

Answer:

Spore formation is a form of asexual reproduction used by mushrooms and molds.

During budding, the offspring grows from the body of the parent.

Fragmentation is a form of asexual reproduction that must be followed by regeneration.

Explanation:

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Consider the above reaction. If some CO2 were removed from the container, what would the reaction do in an attempt to replace th

faltersainse [42]

Answer:

See explanation

Explanation:

The reaction to be considered is shown below;

H2CO3<------->CO2 + H2O

We know that when a constraint such as a sudden change in concentration, pressure or temperature is imposed on a reaction system in equilibrium, the system has to adjust itself by shifting in a particular direction in order to cancel the constraint.

Now, if we remove CO2, the equilibrium position must shift to the right by the decomposition of more H2CO3 to establish equilibrium again.

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3 years ago

formic acid buffer containing 0.50 M HCOOH and 0.50 M HCOONa has a pH of 3.77. What will the pH be after 0.010 mol of NaOH has b

HACTEHA [7]

Answer:

pH = 3.95

Explanation:

It is possible to calculate the pH of a buffer using H-H equation.

pH = pka + log₁₀ [HCOONa] / [HCOOH]

If concentration of [HCOONa] = [HCOOH] = 0.50M and pH = 3.77:

3.77 = pka + log₁₀ [0.50] / [0.50]

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Knowing pKa, the NaOH reacts with HCOOH, thus:

HCOOH + NaOH → HCOONa + H₂O

That means the NaOH you add reacts with HCOOH producing more HCOONa.

Initial moles of 100.0mL = 0.1000L:

[HCOOH] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOOH

[HCOONa] = (0.50mol / L) ₓ 0.1000L = 0.0500moles HCOONa

After the reaction, moles of each species is:

0.0500moles HCOOH - 0.010 moles NaOH (Moles added of NaOH) = 0.0400 moles HCOOH

0.0500moles HCOONa + 0.010 moles NaOH (Moles added of NaOH) = 0.0600 moles HCOONa

With these moles of the buffer, you can calculate pH:

pH = 3.77 + log₁₀ [0.0600] / [0.0400]

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3 years ago

A serving of Frosted Flakes cereal contains 235,000 J of energy. Calculate the change in temperature (ΔT) that would occur if th

timama [110]

The change in temperature (ΔT) : 56.14 ° C

<h3>Further explanation</h3>

Given

Cereal energy = 235,000 J

mass of water = 1000 g

Required

the change in temperature (ΔT)

Solution

Heat can be formulated :

Q = m . c . ΔT

c = specific heat for water = 4.186 J / gram ° C

235000 = 1000 . 4.186 . ΔT

$\tt \Delta T=\dfrac{235000}{1000\times 4.186}=56.14^oC$

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Marrrta [24]

Gravity is responsible !

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2 years ago

What is the boiling point of a 0.75-molal solution of a non-volatile non-electrolyte solute in water? Kb for water = 0.52 degree

AVprozaik [17]

Take the molality and multiply it by the Kb
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then add the boiling pt to the 0.39
100 + 0.39 = 100.39 C

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3 years ago

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