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vodka [1.7K]
3 years ago
9

How many moles of TNT would be detonated if you used 539.88 grams of TNT? The structure of TNT is C7H5N3O6. Round your answer to

two decimal places.
Chemistry
1 answer:
Kruka [31]3 years ago
5 0

Answer:

Moles of TNT = 2.38 moles

Explanation:

First , calculate the molar mass of the compound TNT

The formula is : C7H5N3O6

How to calculate molar mass?

Molar mass : It is the mass of substance in grams which is present in 1 mole of the compound.It is calculated by:

Molar mass = Number of atoms x the atomic mass of the element

Atomic mass of the elements are given below :

C = 12.0107

H = 1.0079

N = 14.0067

O = 15.9994

Molar mass of C7H5N3O6 =

= (7 x C) + (5 x H) + (3 x N) + (6 x O)

= 7(12.0107) +5(1.0079) + 3(14.0067) + 6(15.9994)

Molar mass = 227 .13 gram/mole

Mole are calculated using the formula:

Moles =\frac{given\ mass}{Molar\ mass}

Given mass = 539.88 grams

Molar mass = 227.13 g/mole

Moles =\frac{539.88}{227.13}

= 2.3769

Moles = 2.38 moles

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Answer:

Hydrocarbons

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3 years ago
Suppose 231.8 mgmg of PbCl2PbCl2 was added to 15.0 mLmL of water in a flask, and the solution was allowed to reach equilibrium a
vovangra [49]

Answer:

ksp = 2.2 x ⁻⁴

Explanation:

The equilibrium here is:

PbCl₂ (s)     ⇄ Pb²⁺ + 2 Cl⁻

we can recognize it as a product solubilty equilibrium once we are told that some undissolved PbCl₂ remained.

The equilibrium constant, Ksp is given by the equation

Ksp = [Pb²⁺][Cl⁻]²

where [Pb²⁺] and [Cl⁻]² are the concentrations (M) of Pb²⁺ and Cl⁻ in solution.

we have the mass of solid PbCl₂ placed in solution, so we can determine the number of moles it represents, and if  we  substract the moles of undissolved PbCl₂ we will know the moles of Pb²⁺ and Cl⁻ which went into solution.

From there we can calculate the molarity (M= moles/L solution) and finally plug the values into our expression for Ksp to answer this question.

molar mas PbCl₂ = 278.1 g/mol

1 milligram = 1 x 10⁻³ g

mol PbCl₂ initially = 231.8 x 10⁻³ g / 278.1 mol = 8.3 x 10⁻⁴ mol

Volume solution = 15 mL x 1L / 1000 mL = 0.015 L

mol undissolved PbCl₂ = 74 x 10⁻³ g / 278.1 g/mol = 2.7 x 10⁻⁴ mol

mol PbCl dissolved =   8.3 x 10⁻⁴ mol -  2.7 x 10⁻⁴ mol = 5.7 x 10⁻⁴ mol

Concentration of Pb²⁺ in solution = 5.7 x 10⁻⁴ mol / 0.015 L = 3.8 x 10⁻² M

Concentration of Cl⁻ in solution = 2 x 3.8 x 10⁻² M = 7.6 x 10⁻² M

(Note from the formula we we get 2 mol Cl⁻ per mol PbCl₂)

Plugging these values into the expression for Ksp we have

Ksp = 3.8 x 10⁻² x (7.6 x 10⁻²)² = 2.2 x 10⁻⁴

8 0
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Explanation:

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