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omeli [17]
3 years ago
14

Fragilidad de metales​

Chemistry
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer: La fragilidad es la propiedad de algunos metales de no poder experimentar deformaciones plásticas, de forma que al superar su límite elástico se rompen bruscamente. La acritud es la propiedad de un metal para aumentar su dureza y su resistencia por el efecto de las deformaciones.

Explanation: y estas en el Brianly de ingles no el de español.

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The number of molecules in one mole of lithium acetate are...
Citrus2011 [14]

Answer:

  6.0221409e+23

Explanation:

The number of molecules in a mole of any substance is Avogadro's number, 6.0221409e+23.

8 0
3 years ago
Whats on the right side ?
Svetach [21]

Answer:

B) Products

Explanation:

6 0
3 years ago
Read 2 more answers
Science stuff i got confused can someone pls help. PLS & THX
olga nikolaevna [1]

Answer:

A Scientific Law

Explanation:

'When a substance goes through a chemical change the amount of mass and matter cannot be created nor destroyed.' This a statement of The Law of Conservation of Mass. This Scientific Law is simply titled as a law because every time experimented, the results are predictable and is natural occurrence.

3 0
3 years ago
The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be
dybincka [34]

Answer:

132.17 g

Explanation:

The reaction given , in the question is -

    CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S  ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of  CS₂ .

since ,

Moles of  CS₂  = given mass of CS₂ / Molecular weight  of  CS₂

Since ,

the Molecular weight of  CS₂ = 76

Given ,  mass of CS₂ =  72.57 g

Moles of  CS₂ = 72.57  / 76 = 0.95 mol

Since ,

The yield is 92.0 % .

Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

6 0
3 years ago
A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
hodyreva [135]

Answer:

-252.5 kJ/mol = ΔH H2O(g)

Explanation:

ΔH Fe2O3 = -825.5kJ/mol

ΔH H2 = 0kJ/mol

ΔH Fe = 0kJ/mol

Based on Hess's law, ΔH of a reaction is the sum of ΔH of products - ΔH of reactants. For the reaction:

Fe2O3(s) + 3 H2(g) →2Fe(s) + 3 H2O(g)

ΔHr = 67.9kJ/mol = 3*ΔH H2O + 2*ΔHFe - (ΔH Fe2O3 + 3*Δ H2)

67.9kJ/mol = 3*ΔH H2O + 2*0kJ/mol - (ΔH -825.5kJ/mol + 3*Δ H2)

67.9 = 3*ΔH H2O(g) + 825.5kJ/mol

-757.6kJ/mol = 3*ΔH H2O(g)

<h3>-252.5 kJ/mol = ΔH H2O(g)</h3>
6 0
3 years ago
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