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12345 [234]
3 years ago
15

The __ is the only vein in the body that carries oxygen-rich blood.

Chemistry
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

pulmonary vein

Explanation:

The pulmonary vein is the only vein in the body that carries oxygen rich blood.

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Unit 5 lesson 13 chemistry a catalyst is
kipiarov [429]
A substance that increases the rate of a chemical reaction by lowering the energy of activation
3 0
3 years ago
Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron falls from the n = 7 to the n
Gre4nikov [31]

Answer:

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

Explanation:

The energy of nth energy levels of the H atom is given as:

E_n = -2.18 \times 10^{-18} \times \frac{1}{n^2} J

Energy of the seventh energy level = E_7

E_7=-2.18 \times 10^{-18} \times \frac{1}{7^2} J

E_7=-2.18 \times 10^{-18} \times \frac{1}{7^2} J=-4.4490\times 10^{-20} J

Energy of the seventh energy level = E_4

E_4=-2.18 \times 10^{-18} \times \frac{1}{4^2} J

E_4=-2.18 \times 10^{-18} \times \frac{1}{16} J=-1.3625\times 10^{-19} J

Energy of the light emitted will be equal to the energy difference of the both levels.

E=E_7-E_4=-4.4490\times 10^{-20} J-(-1.3625\times 10^{-19} J)

E=9.176\times 10^{-20} J

Wavelength corresponding to energy E can be calculated by using Planck's equation:

E=\frac{hc}{\lambda }

\lambda =\frac{hc}{E}=\frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{9.176\times 10^{-20}  J}=2.166\times 10^{-6} m=2166 nm

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

8 0
3 years ago
5. The rate constant for the reaction 3A  4B is 6.00 x 10-3 L•mol-1min-1. How long will it take the concentration of A to drop
valkas [14]

Answer:

it will take 444.44 min to reach 0.25 M from 0.75 M

Explanation:

since the reaction constant is k= 6.00*10⁻³ L*mol⁻¹min⁻¹. For a reaction rate of the form

-dCa/dt=k*Caⁿ

doing a dimensional analysis

[dCa/dt]=  mol/(L*min) =   [k]*[Caⁿ] = L/(mol*min) * (mol/L)ⁿ

then only n=2 can comply with the dimensional analysis, therefore we get a the second order reaction . Thus

-dCa/dt=k*Ca²

-dCa/Ca² =k*dt

-∫dCa/Ca² =k*∫dt

(1/Ca₂ - 1/Ca₁)= k*Δt

Δt= 1/k*(1/Ca₂ - 1/Ca₁)

replacing values

Δt= 1/k*(1/Ca₂ - 1/Ca₁) = 1/(6.00*10⁻³ L*mol⁻¹min⁻¹)*(1/0.25 M - 1/0.75 M)= 444.44 min

6 0
4 years ago
Energy naturally moves from a heat source to a heat ______.
guapka [62]
D, none of the above
5 0
2 years ago
How does the chemical structure of water change when it changes state?
Bad White [126]
When the water is heated, the water molecules bounce around and spread out.
When the water is normal, they are pretty close-knit but still flow around. 
When the water is frozen, they are frozen in place and do not move. 
I hope this helped :) 
4 0
3 years ago
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