Answer:
Q = -14322.77 J
Explanation:
Given data:
Mass of water = 55.0 g
Initial temperature = 87.3°C
Final temperature = 25.0 °C
Heat given off = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25.0 °C - 87.3°C
ΔT = - 62.3 °C
Q = 55.0 g×4.18 J/g.°C × - 62.3 °C
Q = -14322.77 J
Answer : The temperature on the Fahrenheit scale was,
Explanation :
The conversion used for the temperature from degree centigrade to Fahrenheit is:
where,
= temperature in Fahrenheit
= temperature in centigrade
As we are given the temperature in degree centigrade is, 45
Now we have to determine the temperature in Fahrenheit.
Therefore, the temperature on the Fahrenheit scale was,
People can reduce their exposure to BPA by washing out plastic cups, buying BPA free plastics. BPA should be kept out because it can cause a chemical interference in the human body
Answer:
Neutrons
Explanation:
Protons have a positive (+) charge.
Electrons have a negative (-) charge.
Neutrons have a neutral (0) charge.
Answer:
the first step in any stoichiometric problem is to always ensure that the chemical reaction you are dealing with is balanced,
Explanation: