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gizmo_the_mogwai [7]
3 years ago
12

Explain how wavelength and frequency are important in determining the type of light.

Physics
2 answers:
Travka [436]3 years ago
4 0

one battery

two switches

two resistors

three light bulbs

Andre45 [30]3 years ago
3 0
It is important to note that the electromagnetic spectrum has a variety of wavelength and frequency of light in it. Some lights we can see, while others are not visual to our naked eye. It is actually very important to determine the kind of light as different lights have different wavelengths and frequencies. some lights are of very high frequency like the gamma rays, while others are of far lower frequency. 
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List the four outer planets from smallest to largest.<br> WILL MARK BRAINLIEST! ASAP
dusya [7]

Answer: Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter.

Explanation:

That's all of the planets if you need them. Hope this helps!

8 0
3 years ago
Help me please!<br> What is the velocity of a 0.1 kg baseball whose momentum is 100?
Nikitich [7]

Answer:

1000m/s

Explanation:

velocity(v)=momentum(p)/mass

=100/.1

=1000m/s

3 0
3 years ago
Why is thermal expansion an important consideration for engineering?
Dennis_Churaev [7]

Answer:

Explanation:

Thermal expansion is where materials expand while being heated, causing them to take up more space. Some materials expand more than others. But this all happens due to the motion of tiny little molecules. Temperature is the average kinetic energy of the molecules in a substance.

Thermal expansion is an important consideration for engineering because different materials exhibit changes in size when exposed to heat. Thus, affecting length, width, surface area, volume, shape etc

8 0
4 years ago
Read 2 more answers
A cannon of mass 5.71 x 103 kg is rigidly bolted to the earth so it can recoil only by a negligible amount. The cannon fires a 7
zheka24 [161]

Answer:

541.14 m/s

Explanation:

We are given that

Mass of cannon=m_1=5.71\times 10^3 kg

Mass of shell,m_2=73.5 kg

Initial velocity of shell,v=547 m/s

We have to find the velocity of shell fired from this loose cannon.

According to law of conservation of momentum

m_1v_1+m_2v_2=m_1u_1+m_2u_2

Initial momentum of system=0

m_1v_1=-m_2v_2

v_1=-\frac{m_2v_2}{m_1}

When the cannon is bolted to the ground then only shell moves and kinetic energy of system equals to kinetic energy of shell

Kinetic energy of shell,K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 73.5(547)^2}=1.09\times 10^7 J

K.E of shell=\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2

K.E of shell=\frac{1}{2}m_1(-\frac{m_2v_2}{m_1})^2+\frac{1}{2}m_2v^2_2

K.E of shell=\frac{1}{2}(\frac{m^2_2v^2_2}{m_1}+\frac{1}{2}m_2v^2_2)

2K.E of shell=m_2v^2_2(\frac{m_2}{m_1}+1)

Velocity of shell fired from this loose cannon,v_2=\sqrt{\frac{2k.E}{m_2(\frac{m_2}{m_1}+1)}

v_2=\sqrt{\frac{2\times 1.09\times 10^7}{73.5(\frac{73.5}{5.71\times 10^3}+1)}

v_2=541.14m/s

Hence, the velocity of shell fired from this loose cannon would be 541.14 m/s

5 0
3 years ago
The Earth's diameter at the poles is _____.
maria [59]
Less than it’s diameter at the equator
4 0
3 years ago
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