Centripetal acceleration is given by:
a = v²/r
a = centripetal acceleration, v = speed of cylinder at surface, r = radius of cylinder
This equation relates the speed of the cylinder at its surface to its angular velocity:
v = rω
v = speed at surface, r = radius, ω = angular velocity
Make a substitution:
a = (rω)²/r
a = rω²
Given values:
a = 9.81m/s², r = (5.0mi)/2 = 2.5mi = 4023m
Plug in and solve for ω:
9.81 = 4023ω²
ω = 0.049rad/s
Answer: Northwest.
Explanation:
After the collision the second object which was at rest would change its direction and move towards the Northwest. The object in motion was coming from the east and traveling towards the west, where it deflects against a stationery object which changes its direction to southeast. And the object which was at rest moves toward the northwest.
Explanation:
because his lower body is in inertia of motion.
Hope it helps
Answer:
a)r' = 4 r
b)
Explanation:
Given that car is moving with uniform speed.
At the verge of sliding
Friction force = Force due to circular motion
![\mu mg=\dfrac{mV^2}{r}](https://tex.z-dn.net/?f=%5Cmu%20mg%3D%5Cdfrac%7BmV%5E2%7D%7Br%7D)
So we can say that
-----1
Where is the coefficient of friction
r is the radius of circular path
V is the velocity of car
a)
if the car speed become double
It means that new speed of car =2V
lets tale new radius of circular path is r'
---------2
From equation 12 and 2 we cay that
r' = 4 r
It means that we have to increase radius 4 times to avoid sliding
b)
In the above expression there is no any terms of mass ,it means that sliding speed does not depends on the weight of car.
So the sliding speed will remain same.
Net force is basically the force an object has when changing direction, so the answer would be D.