The sun. The more mass an object has, the greater gravitational pull it will have, as mass attracts other mass.
The energy that would be released if the mass was converted to energy is 9 * 10^-4 J
<h3>What is Einstein equation?</h3>
According to the Einstein equation, mass and energy can be interconverted. This is possible by the use of the equation E = mc^2
Where;
m = mass
c = speed of light
Hence;
E = 1 * 10^-20 Kg * (3 * 10^8 m/s)^2
E = 9 * 10^-4 J
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Answer:
745.4K ~ 472.3 C
Explanation:
This is an Ideal Gas Law problem where we have to manipulate the equation a bit. Let's start with the basic:
PV = nRT will be used for both the initial and final, so we will rearrange this problem to state:
(V(initial))/(T(Initial)) = nR/P
Since we know that the pressure, number of moles of He, and ideal gas constant (R) remain the same from start to finish so we can write the problem as such:
(V(initial))/(T(Initial)) = nR/P = (V(final))/(T(final))
or
(V(initial))/(T(Initial)) = (V(final))/(T(final))
Now lets define some of these values:
T(initial) = 25degree (assuming degrees Celsius) ~ 298.15K
V(initial) = 2.0L
V(final) = 5.0L
T(final) = ?
Since we are solving for T(final) let's rearrange the problem once more to be solving for T(final):
T(final) = (V(final)T(Initial))/V(initial)
Now plug in your values:
T(final) = (5.0L*298.15K)/(2.0L) ~ 745.4K ~ 472.3degrees Celsius
The rms potential difference is defined as the peak value of the potential difference divided by the square root of 2:
where
is the peak value of the voltage (the maximum voltage).
The generator in our problem has a maximum voltage of
, so its rms potential difference is
Since
Electric potential energy = qV
Where V = Ed
Hence
Electric potential energy = q(Ed) --- (1)
Since E = 1.0 * 10^3 N/C
d = 0.10 m
q = 4 * 10^-6 C
Plug in the values in (1)
(1) => Electric potential energy = 4 * 10^-6(1.0 * 10^3 * 0.10)
Electric potential energy = 400 μJ