2 years ago

HELP ME FAST PLZZ 48 BRAINLY POINTS TO WHO EVER ANSWER!

Physics

2 answers:

Elis [28]2 years ago

4 0

Answer:

Explanation:

I looked at it and its 25

meriva2 years ago

3 0

The answer is 20. W= 22, X= 18, Y= 35, Z= 24. If the substance has less kinetic energy than substance Z (24) but more kinetic energy than substance X (18), the answer choice that works is 20.

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Approximately how many atoms are there along a 9.5 cm line

uranmaximum [27]

First convert 5.5 cm to meters.

(5.5 cm / 1) x (m / 100 cm) = 0.055 m

A typical atom is about 1.0E-10 m in diameter; thus:

0.055 m / 1.0E-10 m = 5.5E8 atoms or 550,000,000 end-to-end atoms in 5.5 cm

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3 years ago

A metal bar has a frictionless axle going through its center of mass. You notice that the bar is not level (flat), but that it i

ANTONII [103]

Answer:

yep

Explanation:

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A cart travels down a ramp at an average speed of 5.00 centimeters/second. What is the speed of the cart in miles/hour? (Remembe

viva [34]

Set up the problem with the conversion rates as fractions where when you multiply the units cancel out leaving the desired units behind.

$( \frac{ 5 cm}{1 sec} ) *( \frac{1m }{100cm})*( \frac{1km}{1000m} )*( \frac{1mi}{1.6km} ) = 0.00003125 mi/sec \\ \\ ( \frac{0.00003125 mi}{1sec} )*( \frac{60sec}{1min} )*( \frac{60min}{1hr} )=0.1125 mi/hr$

7 0

3 years ago

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What would happen to a moving object if no unbalanced force acts upon it?<br> Help please?

Kisachek [45]

Answer:

Explanation:

if no force acts upon it it will just continue moving

hope this helps!! have a wonderfull day!

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3 years ago

Derive the kinetic equations for Vmax and KM using the transit time and net rate constant method as discussed in class and follo

Pepsi [2]

Answer:

Rate = vmax k3/k2+k3

Explanation:

The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, is referred to as Vmax.

This is usually expressed as the Km ie. Michaelis constant of the enzyme, an inverse measure of affinity. For practical purposes, Km is the concentration of substrate which permits the enzyme to achieve half Vmax.

Please kindly check attachment for the step by step solution of the given problem.

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3 years ago