Answer:
The weight of the bird is equal to 7.28 N.
Explanation:
The upward force acting on the bird = 7.28 N
The bird is climbing at a constant rate of 1 m/s.
We need to find the weight of the bird.
We know that the weight of an object is the force of gravity acting on it. It can be calculated as follows :
W = mg
In this case, 7.28 N of force is acting on the object. Hence, the weight of the bird is equal to 7.28 N.
Hello!!
For the maximum height the final velocity is zero, <u>because can't up more.</u>
Then, use the formula:
V = Vi + gt
Replacing, we have:
0 m/s = 5,3 m/s + (-9,8 m/s² * t)
0 m/s - 5,3 m/s = -9,8 m/s² * t
(-5,3 m/s) / -9,8 m/s² = t
t = 0,54 s
The time it will take to reach the maximum height is <u>0,54 seconds.</u>
3.285 × 10^23 kg is the approximate mass of mercury
the positive and negative charges distribution contribute equally to the electric field inside each capacitor? If not, what fraction of the field comes from the negative distribution is given below
Explanation:
1.Capacitors store energy by holding apart pairs of opposite charges. Since a positive charge and a negative charge attract each other and naturally want to come together, when they are held a fixed distance apart (for example, by a gap of insulating material such as air), their mutual attraction stores potential energy that is released if they are re-united.
2.The simplest design for a capacitor is a parallel-plate, which consists of two metal plates with a gap between them: electrons are placed onto one plate (the negative plate), while an equal amount of electrons are removed from the other plate (the positive plate).
3.Charges create electric field lines that point away from positive charges and towards negative charges. In a parallel-plate capacitor, the electric field lines point straight across the gap between the two plates. We know that electric fields and voltage differences go hand-in-hand, and so it also turns out that the two plates are at different voltages. The size of this voltage difference (V) is related to the charges on the two plates (Q):
Q= C V
The constant C is called the capacitance. It determines how much of a charge difference the capacitor holds when a certain voltage is applied.
