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Ad libitum [116K]
3 years ago
10

Sabrina took out a loan for $60,000 to pay for her child's education. The loan must be repaid at the end of eight years in one p

ayment with interest of 6%. The total amount Sabrina has to pay back at the end of the loan is
Mathematics
2 answers:
satela [25.4K]3 years ago
8 0
I hope this will help u !!!!
6% means 6/100 so
loan took=$60,000
loan she has to pay= 60,000×6/100 = 600×6 = 3600
:: she has to pay $60,000 + 3600 = $63,600
thankyou
umka2103 [35]3 years ago
7 0

One way of doing this would be to begin with $60,000, calculate the interest, and then add the interest to this $60,000:

$60,000 + $60,000(0.06)(8) = $88,800.

Sabrina will have to repay $88,800.

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If the principle is $12,000 and the rate of interest is 6% (simple interest), what
Elza [17]

9514 1404 393

Answer:

  $12,720

Step-by-step explanation:

The amount is given by the formula ...

  A = P(1 +rt)

where P is the principal, invested at rate r for t years.

  A = $12,000(1 +0.06·1) = $12,720

The total amount after 1 year is $12,720.

7 0
3 years ago
Plz help will mark you brainliest if correct
inn [45]

Answer:

B

Step-by-step explanation:

5/1 is not equal to 6/2 or 7/3 or 8/4

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=5x-%20%5Cdfrac%7B%20%5Csqrt%7B%209%20%7B%20x%20%7D%5E%7B%202%20%7D%20-6x%2B1%20%5Cphantom%7B%5
Morgarella [4.7K]

Answer:

=5x+1          or          =5x-1

Step-by-step explanation:

One is given the following equation:

5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation.  Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

(a-b)^2=a^2-2ab+b^2

=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}

=5x-\frac{|3x-1|}{-(3x-1)}

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

|a-b|\\=a -b           or           (-a-b) = b-a

=5x-\frac{|3x-1|}{-(3x-1)}

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

=5x-(-1)          or          =5x-(1)

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

=5x-(-1)          or          =5x-(1)

=5x+1          or          =5x-1

6 0
2 years ago
There are 8 times as many females as males on the maths course at university. What fraction
Serga [27]

Answer:

8/9 of the course are males.

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2 years ago
2/4 plus 1/3 as a fraction
QveST [7]

Answer: 5/6

Step-by-step explanation: trust me on this

7 0
3 years ago
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