Answer:
Increase in temperature = 269.54 °C
Explanation:
We have equation for thermal expansion
ΔL = LαΔT
Change in length, ΔL = 0.08 m
Length, L = 56 m
Coefficient of thermal expansion, α = 5.3 x 10⁻⁶ °C⁻1
Change in temperature, ΔT = T - 253
Substituting
0.08 = 56 x 5.3 x 10⁻⁶ x (T - 253)
(T - 253) = 269.54
T = 522.54 °C
Increase in temperature = 269.54 °C
Answer:
1800 m/
Explanation:
We know this because of Newton's first law, 
, which shows us that the force on an object is equal to its mass times the acceleration it recieves. This means that taking our values of 900N and 0.5kg, and plugging them in,
This is honestly a little strange because the force applied and the acceleration seem ridiculous, and a little strange for an answer. Either the values are not meant to be nearly close to reality, or you made a typo.
Answer:
TRUE
Explanation:
Balance forces are usually defined as the two distinct force that acts on an object but in opposite directions. These two acting forces are equal in size or magnitude. When this type of force is applied on any object, it signifies that the object is stationary or it is moving at a constant speed and in the same direction.
This force is comprised of two most important properties namely the strength and direction. When any of the two forces is higher then it result in the motion of the object.
Thus, the above given statement is TRUE.
Answer:
Explanation:
Given that,
Current in loops are
i1 = 12A
i2 = 20A
The loops are 3.4cm apart
The magnetic field at the center is found to be zero, so when want to find the radius of bigger loop
Magnetic Field is given as
B= μoi/2πr
Where,
μo is a constant = 4π×10^-7 Tm/A
r is the distance between the two wires
i is the current in the wires
B is the magnetic field
NOTE
Field due to large loop should be equal to the smaller loop.
B1 = B2
μo•i1 / 2π•r1 = μo•i2 / 2π•r2
Then, μo, 2π cancels out, so we have
i1 / r1 = i2 / r2
Make r2 subject of formula
i1•r2 = i2•r1
r2 = i2•r1 / i2
r2 = 20×3.4/12
r2 = 5.67cm
The radius of the bigger loop is 5.67cm.
Answer:
TIME he applied the fertilizer to each plant
Explanation:
Independent variable in an experiment is the variable that is subject to change or manipulation by the experimenter. In this experiment, Bob wanted to investigate the effects of plant fertilizer. Bob sets up the experiment by applying the fertilizer to each plant at DIFFERENT TIMES i.e. plant 1-every morning, plant 2-once a week, plant 3-never.
Based on this, it is obvious that the independent or manipulated variable is the TIME at which he applied the fertilizer. On the other hand, the dependent or measured variable is the height of the plants.
