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2 years ago

The very strong source of radio waves at the center of our galaxy is called.

Physics

1 answer:

Alika [10]2 years ago

4 0

The answer is Sagittarius A, a very large black hole.

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What is the frequency of orange light is it has a wavelength of 6.2 x 10^-6<br> meters?

Tanya [424]

λ=v/f

λ-wavelength

v-speed

f-frequency

we have the wavelength(6.2 x 10^-6meters) and we use the speed of light which is equal to 3*10^8m/s

6.2*10^-6m=3*10^8m/s/f

f=(3*10^8m/s)/(6.2*10^-6)≈0.48*10^14Hz

6 0

2 years ago

Read 2 more answers

In these formulas, it is useful to understand which variables are parameters that specify the nature of the wave. The variables

Juli2301 [7.4K]

They made me do it I don’t even know what to say I’m so sorry

7 0

2 years ago

What is an example of light energy converted into heat energy?

Andreyy89

Answer:

Sun

Explanation:

Sun Can Give Us Light Energy And It convert Into Heat Energy

3 0

2 years ago

A 2.55 kg block starts from rest on a rough inclined plane that makes an angle of 60 degree with the horizontal. the coefficient

lorasvet [3.4K]

Answer:

Change in mechanical energy = work done by friction

so it is equal to

$W = -8.16 J$

Explanation:

As we know that change in mechanical energy must be equal to the work done by non conservative forces only

So here when block moves down the inclined plane then the work done by friction force is given as

$W = F.d$

here we have

$F = \mu F_n$

here we know that

$F_n = mg cos\theta$

so we have

$F_n = 2.55(9.81)(cos60)$

$F_n = 12.5 N$

Now the friction force on the block is given as

$F_f = \mu F_n$

$F_f = 0.25 \times 12.5$

$F_f = 3.13 N$

now work done by the friction is given as

$W = -(3.13)(2.61)$

$W = -8.16 J$

7 0

3 years ago

A 50.1 kg diver steps off a diving board and drops straight down into the water. The water provides an average net force of resi

Varvara68 [4.7K]

Answer:

The total distance is 16.9 m

Explanation:

We understand work in physics as certain force exerted through certain distance. To reach that point below the water, the work done by the diver must be equal to the work done by the water's force of resistance. Therefore, we determine both work expressions and we solve the equation for the diver distance, which is the total distance between the diving board and the stopping point underwater.

$W_{d}: work done by diver\\W_{R}: work due the force of resistance\\W_{d} = W_{R}\\F_{d}\times d_{d}=F_R \times d_{R}\\d_{d}= \frac{F_R \times d_R}{F_d}= \frac{F_R \times d_R}{m_d \times g}= \frac {1598 N \times 5.2 m}{50.1 kg \times 9.81 m/s^2}\\d_{d}= 16. 91 m$

7 0

2 years ago