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kvasek [131]
3 years ago
7

A small rocket to gather weather data is launched straight up. Several seconds into the flight, its velocity is 140 m/s and it i

s accelerating at 20 m/s2 . At this instant, the rocket's mass is 51 kg and it is losing mass at the rate of 0.50 kg/s as it burns fuel. What is the net force on the rocket?
Physics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Explanation:

The force will be 98 N....

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olganol [36]
D is your answer <span>have highly predictable orbits around the sun. </span>
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3 years ago
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A neutral metal sphere is attracted to a positively-charged amber rod. Why does this occur?.
aniked [119]

Hi there!

A neutral metal sphere is comprised of both ELECTRONS and PROTONS.

Recall that electrons have a NEGATIVE (-) charge, and protons have a POSITIVE (+) charge.

Opposite charges attract, and like charges repel.

In this instance, the positively-charged rod will cause the electrons in the neutral metal sphere to move towards the side facing the rod (opposite charges attract), which causes the two to be attracted to one another.

3 0
2 years ago
Pulsars are neutron stars that emit X rays and other radiation in such a way that we on Earth receive pulses of radiation from t
stira [4]

Answer:

(a) a_{c} = 5.41\times 10^{9} m/s^{2}

(b) a_{t} = 2.99\times 10^{- 5} m/s^{2}

Given:

Time period of Pulsar, T_{P} = 33.085 ms == 33.085\times 10^{- 3} s

Equatorial radius, R = 15 Km = 15000 m

Spinning time, t_{s} = 9.50\times 10^{10}

Solution:

(a) To calculate the value of the centripetal  acceleration, a_{c} on the surface of the equator, the force acting is given by the centripetal force:

m\times a_{c} = \frac{mv_{c}^{2}}{R}

a_{c} = \frac{v_{c}^{2}}{R}                (1)

where

v_{c} = \frac{distance covered(i.e., circumference)}{ T}

v_{c} = \frac{2\pi R}{Time period, T}           (2)

Now, from (1) and (2):

a_{c} = R\frac({2\pi )^{2}}{T^{2}}

a_{c} = 15000\frac{2\pi )^{2}}{(33.085\times 10^{- 3})^{2}}

a_{c} = 5.41\times 10^{9} m/s^{2}

(b) To calculate the tangential acceleration of the object :

The tangential acceleration of the object  will remain constant and is given by the equation of motion as:

v = u + a_{t}t_{s} = 0

where

u = v_{c}

a_{t} = - \frac{2\pi R}{Tt_{s}}

a_{t} = - \frac{2\pi 15000}{33.085\times 10^{- 3}\times 9.50\times 10^{10}}

a_{t} = 2.99\times 10^{- 5} m/s^{2}

7 0
3 years ago
Can someone please answer this, ill give you brainliest Would be very appreciated.
mina [271]

Water cycle basically involves the change of water into liquid to vapour and again to liquid states through a cyclic manner .

The answers are

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  2. Transpiration
  3. Condensation
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5 0
2 years ago
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A student pushes a 40-N block across the floor for a distance of 10 m. How much work was applied to move the block? A. 4 J B. 40
damaskus [11]
Now for this problem, what is given is a 40 Newtons which would represent the force to be applied to the object, and a distance of 10 meters after the application of the said force. When these two combine, work is done. The unit for work is Joules and this is what we are looking for. The formula to get Joules or for work would be the force applied to the object multiplied by the distance that it travelled after the application of the force. It looks like this

work = force x distance
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so let us substitute the variables to their corresponding places

Joules = 40 N x 10 m
Joules = 400 J

So the answer to this question would be C. 400 J
7 0
3 years ago
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