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motikmotik
3 years ago
13

What is the displacement of the GBS cross-country team if they begin at the school, run 10 miles, and finish back at the school?

Physics
1 answer:
olga2289 [7]3 years ago
8 0

Answer:

0

Explanation:

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A 55-kg woman is wearing high heels.
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Answer:

Pressure, P=1.90\times 10^7\ Pa        

Explanation:

It is given that,

Mass of the woman, m = 55 kg

Diameter of the circular cross section, d = 6 mm

Radius, r = 3 mm = 0.003 m

Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :

P=\dfrac{F}{A}

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P=1.90\times 10^7\ Pa

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4 years ago
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8 0
3 years ago
Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) .
jek_recluse [69]

Explanation:

Given that,

Force, F=((-8i)+6j)\ N

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Taking the cross product of above two vectors, we get the value of torque as :

\tau=(0+0-50k)\ N-m

(b) Let \theta is the angle between r and F. The angle between two vectors is given by :

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cos\theta=\dfrac{(3i+4j).((-8i)+6j)}{(\sqrt{3^2+4^2} ).(\sqrt{8^2+6^2}) }

cos\theta=\dfrac{0}{50}

\theta=90^{\circ}

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