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3 years ago

What two measurements are needed to determine density?

2 answers:

7 0

Density is defined as (mass) per unit (volume). So in order to calculate
the density of a glob of some substance, you pretty much have to measure
its mass and its volume.

svp [43]3 years ago

4 0

mass & volume

$Density = \frac{mass}{volume}$

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Can someone help me define “Celestial roles”? I can’t find it in my textbook, and when I look it up it just shows Marvel stuff.

Soloha48 [4]

Answer:

iam not getting about celestial roles ,here is the meaning of celestial

Explanation:

The first is something living such as an alien or an angel, whereas the latter is an inanimate object such as a star or a planet. Both, however, are from the sky. The word celestial is primarily used to describe things that have to do with the heavens such as angels, spirits, stars and planets.

4 0

3 years ago

Read 2 more answers

A projectile is launched at ground level with an initial speed of 50.0m/s at an angle of 30° above the horizontal. It strikes a

tino4ka555 [31]

Answer:

x = 129.9 m

y = 30.9 m

Explanation:

When an object is thrown into the air under the effect of the gravitational force, the movement of the projectile is observed. Then it can be considered as two separate motions, horizontal motion and vertical motion. Both motions are different, so that they can be handled independently.

Given data:

$v_{i}$ = 50 m/s

Angle = 30°

Time = t = 3 s

horizontal component of velocity = $v_{i_{x}}$ = $v_{i}$ cos30°

$v_{i_{x}}$ = 50cos30°

$v_{i_{x}}$ = 43.3 m/s

Vertical component of velocity = $v_{i_{y}}$ = $v_{i}$ Sin30°

$v_{i_{y}}$ = 50Sin30°

$v_{i_{y}}$ = 25 m/s

This is a projectile motion, and we know that in projectile motion the horizontal component of the velocity remain constant throughout his motion. So there is no acceleration along horizontal path.

But the vertical component of velocity varies with time and there is an acceleration along vertical direction which is equal to gravitational acceleration g.

Horizontal distance = x = $v_{i_{x}}$ t

x = 43.3*3

x = 129.9 m

Vertical Distance = y = $v_{i_{y}}$ t -0.5gt²

y = 25*3 - 0.5*9.8*3²

y = 75 - 44.1

y = 30.9 m

3 0

4 years ago

Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

tresset_1 [31]

We are given with the data that the angle of velocity is above the negative axis. hence, the angle lies in the second quadrant with negative x axis and positive y axis. In this case, the x component is -12 cos 60 equal to -6 m/s while the y-component is 12 sin 60 equal to 6 sqrt of 3 m/s.

6 0

3 years ago

Which sentence describe newton's third law?

strojnjashka [21]

C. Forces are always in pairs

3 0

3 years ago

A permanent magnet is placed near a bar of soft iron PQ what will happen

boyakko [2]

Answer:

it will rust

Explanation:

hope it helps

4 0

3 years ago