What compounds are you made of?

2 answers:

6 0

I am made of literally THOUSANDS of compounds ... too many to list here.
But the one compound that's most abundant, and actually comprises almost
80% of my entire beautiful body, is the compound DiHydrogen Oxide, with
the molecular formula H₂O . This compound is commonly known as "water".

tamaranim1 [39]3 years ago

5 0

Thousands of compounds

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3 years ago

A train takes ms eaddy 200 miles north and 150 miles south. The total trip took 3.5 hours what was the average velocity of the t

Verizon [17]

The whole point of this problem is to check how well you understand
the definitions of a few important quantities, like velocity, speed, distance,
displacement etc.

Before we begin, I just want to mention that 'MPG' is not a unit of either
velocity or speed, but I think I know what you mean.

-- For some reason, Ms. Eaddy rode 100 miles north on the train, then
stayed aboard while the train turned around and took her 150 miles south.
The total distance she rode was (100 + 150) = 250 miles. But she ended up
50 miles south of where she began.

-- Displacement for the whole trip = distance and direction from the start point
to the finish point.

Displacement = 50 miles south

-- Average velocity = (displacement) / (time)

50 miles south / 3.5 hours = <u>14.29 miles per hour south</u>

3 0

3 years ago

True or False : Waves lose most of their energy when traveling across the ocean.

klemol [59]

Answer:

true

Explanation:

that's the answear

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2 years ago

Read 2 more answers

In the mobile m1=0.42 kg and m2=0.47 kg. What must the unknown distance to the nearest tenth of a cm be if the masses are to be

LuckyWell [14K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

The first mass is $m_1 = 0.42kg$

The second mass is $m_2 = 0.47kg$

From the question we can see that at equilibrium the moment about the point where the string holding the bar (where $m_1 \ and \ m_2$ are hanged ) is attached is zero

Therefore we can say that

$m_1 * 15cm = m_2 * xcm$

Making x the subject of the formula

$x = \frac{m_1 * 15}{m_2}$

$= \frac{0.42 * 15}{0.47}$

$x = 13.4 cm$

Looking at the diagram we can see that the tension T on the string holding the bar where $m_1 \ and \ m_2$ are hanged is as a result of the masses ( $m_1 + m_2$ )