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4 years ago

If a car goes at a speed of 80 kph in 10 seconds, what is the distance

Physics

1 answer:

Blababa [14]4 years ago

3 0

Answer:222 meters

Explanation:

Speed=80kph=(80x5/18)=(80x5)/18=22.2m/s

Time=10 seconds

distance=speed x time

distance=22.2 x 10

distance=222

distance=222 meters

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Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the sea, a rock sticks out a horizontal dis

Stella [2.4K]

Answer:

$v_x = 4.87 m/s$

Explanation:

Height of the cliff is given as

$h = 37.1 m$

now the time taken by the diver to hit the surface is given as

$h = \frac{1}{2}gt^2$

$37.1 = \frac{1}{2}(9.8)t^2$

$t = 2.75 s$

Now in the same time it has to cover a distance of 13.39 m

so the speed in horizontal direction is given as

$v_x = \frac{x}{t}$

$v_x = \frac{13.39}{2.75}$

$v_x = 4.87 m/s$

3 0

4 years ago

Which of the following statement(s) about energy and phase is/are correct? Select all that apply. Choose one or more: A. While o

Free_Kalibri [48]

Answer: Option (A) and (D) are the correct statements.

Explanation:

Potential energy is defined as the energy obtained by an object due to its position. Whereas kinetic energy is defined as the energy obtained by an object due to the motion of its molecules.

When there will be only one phase present then addition or removal of energy will lead to change in kinetic energy of the substance but no change in potential energy will take place.

Whereas if change in phase is occurring then adding or removing any energy will lead to change in potential energy of the substance while kinetic energy will remain the same.

Thus, we can conclude that correct statements are as follows.

While only one phase is present, adding or removing energy changes PE but not KE.

During a phase change, adding or removing energy changes PE but not KE.

3 0

4 years ago

Consider an object with weight on the Earth W_earth. The gravity of the Earth is g. If it is moved to another planet with gravit

Mazyrski [523]

Answer:

$W_{Planet} = \frac{W_{Earth}}{g}\times a$

Explanation:

We know that weight of an object on Earth is,

$W_{Earth} = m\times g$

Thus,

$m = \frac{W_{Earth}}{g}$

where,

m = mass of an object, which is constant and is independent of gravity

g = acceleration due to gravity on Earth

On the new planet, gravity = a

Thus the weight of the object on the new planet will be

$W_{Planet} = m\times a$

$W_{Planet} = \frac{W_{Earth}}{g}\times a$

5 0

3 years ago

The wind is blowing horizontally at 30 m / s in a storm at P o , 20°C toward a wall, where it comes to a stop (stagnation) and l

aleksklad [387]

Answer:

To=20.44 °C

Explanation:

Given that

Velocity , v= 30 m/s

Temperature , T= 20°C

We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K

By using energy conservation ,the stagnation temperature is given as

$T_0=T+\dfrac{v^2}{2C_p}$

Now by putting the values in the above equation we get

$T_0=(20+273)+\dfrac{30^2}{2\times 1.005\times 1000}\ K$

To= 293.44 K

To= 293.44 - 273 °C

To=20.44 °C

Therefore the stagnation temperature will be 20.44 °C.

3 0

3 years ago

A bob attached to a string of length L = 1.25 m, initially found at the equilibrium

malfutka [58]

The maximum displacement angle of the bob is 13⁰.

The given parameters;

<em>Length of the pendulum, L = 1.25 m</em>
<em>Initial velocity of the bob, v = 0.8 m/s</em>

The maximum displacement of the bob is calculated by applying the principle of conservation of energy;

$P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m$

The maximum displacement angle is calculated as follows;

$cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0$

Thus, the maximum displacement angle of the bob is 13⁰.

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4 0

3 years ago