Answer:
Asch (1956) found that group size influenced whether subjects conformed. The bigger the majority group (no of confederates), the more people conformed, but only up to a certain point.
Explanation:
2m/s
Explanation:
Given parameters:
Distance traveled = 60m
time taken = 30seconds
Unknown:
Speed of skateboarder = ?
Solution:
Speed is the rate of change of distance with time taken. It is a scalar quantity that only revers magnitude;
Speed = 
Speed =
= 2m/s
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Answer:
The work done by gravity is 
Explanation:
The data given in the question is :
Mass is 
Height from ground is 
As we know , the work done is state function , it depends on initial and final position not on the path followed.
So, work done by gravity = change in potential energy
Work done = Initial potential energy - final potential energy
Insert values from question
Work done = 
Work done = 
So, work done = 
Hence the work done by gravity is 
It is important to look at all the information's that are given in the question very closely. Let us write them write first.
Radius of the spa = <span>5/√2-1 feet
Now
Perimeter of the circle = </span><span>2πr
= 2</span>π (5/√2-1)
= <span>π(5/(√2-1)*(√2+1)/(√2+1) </span>
<span> = 2π(5/(√2+1))/(2-1) </span>
<span> = 10π(√2+1)
I hope that the procedure is clear enough for you to understand.</span>
Answer:
i) No, the spring scale does not read a different value
ii) The torque will read a different value, it will reduce
iii) The spring scale does not need to be measured at the center of mass location.
Explanation:
The torque caused by the gyroscope can be given by the relation,
r × f

The torque measured by the gyroscope varies directly with the distance, r.
A decrease in the distance r will also cause a decrease in the value of the torque measured. When the distance, r is reduced from 7.5 inches to 5 inches, the torque caused by the gyroscope's weight also reduces.
The weight of the gyroscope remains constant despite the reduction in the distance because the weight of the gyroscope is not a function of the distance from the gyroscope. Therefore, the spring scale will not read a different value.
Yes, the spring scale does not need to be measured from the center of mass location because the weight does not depend on the location of measurement. The reading of the sprig scale remains constant.