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tia_tia [17]
3 years ago
5

What quantum numbers specify these subshells 5s 6p 4d?

Chemistry
1 answer:
shutvik [7]3 years ago
7 0
Quantum numbers are used to describe the location of electrons in atoms. 
Principal quantum number(n) tells which energy shell the electrons reside in.
The first energy shell n = 1, second energy shell n = 2 and it goes on.
Azimuthal quantum number (l) states which orbital the electron is most likely to reside in. the number of orbitals in an energy shell depends on the principal quantum number. number of orbitals are from 0 to  n-1 
If l = 0, s orbital 
   l = 1 , p orbital 
   l = 2, d orbital
in 2nd energy shell the number of orbitals are 0,1 etc.

5s-
Principal quantum number n = 5
Azimuthal quantum number l = 0

6p
Principal quantum number n = 6
Azimuthal quantum number l = 1

4d
Principal quantum number n = 4
Azimuthal quantum number l = 2
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Carbon dioxide and helium which has a higher van der waals force of attraction between molecules ​
raketka [301]

Answer:

Carbon dioxide  

Explanation:

Neither helium nor carbon dioxide has a molecular dipole, so their strongest van der Waals attractive forces are London forces.

Helium is a small spherical atom with only a two electrons, so its atoms have quite weak attractions to each other.

CO₂ is a large linear molecule. It has more electrons than helium, so the attractive forces are greater. Furthermore, the molecules can align themselves compactly side-by-side and maximize the attractions (see below).

For example. CO₂ becomes a solid at -78 °C, but helium must be cooled to -272 °C to make it freeze (that's just 1 °C above absolute zero).

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3 years ago
Consider the insoluble compound nickel(II) hydroxide , Ni(OH)2 . The nickel ion also forms a complex with cyanide ions . Write a
natali 33 [55]

Answer: Equilibrium constant for this reaction is 2.8 \times 10^{15}.

Explanation:

Chemical reaction equation for the formation of nickel cyanide complex is as follows.

Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)

We know that,

      K = K_{f} \times K_{sp}

We are given that, K_{f} = 1.0 \times 10^{31}

and,    K_{sp} = 2.8 \times 10^{-16}

Hence, we will calculate the value of K as follows.

     K = K_{f} \times K_{sp}

     K = (1.0 \times 10^{31}) \times (2.8 \times 10^{-16})

        = 2.8 \times 10^{15}

Thus, we can conclude that equilibrium constant for this reaction is 2.8 \times 10^{15}.

4 0
3 years ago
What is the primary requirement for a molecule to be analyzed by Gas Chromatography?
BabaBlast [244]

Answer:

b) The molecule has a molecular weight under 200 g/mole

Explanation:

The molecule has a molecular weight under 200 g/mole is the primary requirement for a molecule to be analyzed by Gas Chromatography.

3 0
3 years ago
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Consider separate samples of water and carbon dioxide, each with the same mass. Which contains the greater number of molecules?
Ahat [919]

Answer: The sample that contains the greater number of molecules is water.

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moles =\frac{mass}{molar weight}

To water: moles = \frac{1g}{18 g/mol} = 0.05 moles.

Therefore,

1 mol ---- 6.02*10^{23} molecules

0.05 moles ---- x

x = 0.30*10^{23} molecules of water.

To carbon dioxide: moles = \frac{1g}{44 g/mol} = 0.02 moles.

Therefore,

1 mol ---- 6.02*10^{23} molecules

0.02 moles ---- y

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