Given:
0.060 mol of NiC2O4
Ksp = 4 x 10⁻¹⁰
1.0 L of solution
Kf of Ni(NH3)6 2⁺ = 1.2 x 10⁹
<span>NiC2O4 + 6NH3 ⇋ Ni(NH3)6 2+ + 2O4 2- </span>
<span>NiC2O4 ⇋ Ni 2+ + C2O4 2- ...Ksp </span>
<span>Ni2+ + 6NH3 ⇋ Ni(NH3)6 2+...Kf </span>
Ksp * Kf = (4 x 10⁻¹⁰) * (1.2 x 10⁹) = 0.48
K = 0.48 = [Ni(NH3)6 2+][C2O4 2-] / [NH3]⁶<span>
</span>0.48 = (0.060)² / [NH3]⁶<span> ... (dissolved C2O4 2- = 0.060M)
</span><span>[NH3]</span>⁶<span> = (0.060)</span>²<span> / 0.48 = </span>0.0036 / 0.48 = 0.0075
NH3 = ⁶√0.0075
NH3 = 0.44 M
Answer:
D
Explanation:
Sweat glands remove waste
Answer:
16 mol O2
Explanation:
CO + 2 O2 -> 2 CO2
1 mol CO -> 2 mol O2
8 mol CO -> x
x= (8 mol CO * 2 mol O2)/1 mol CO
x= 16 mol O2
A. Identify the properties as either a physical or chemical property. (first 3 are chemical, last is physical)
Answer:
The equation showing the dissolving of solid ammonium phosphate in water is: (NH4)3 PO4 (s) → 3NH4 +1 (aq) + PO4 -3 (aq).
Explanation:
