Mass of 1 centigram is equal to 0.01 grams
So, option C is your answer!
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Answer:
step 2
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Answer:
a) 24.7 mol
b) 790 g
Explanation:
Step 1: Given data
- Volume of the chamber (V): 200. L
- Room temperature (T): 23 °C
- Pressure of the gas (P): 3.00 atm
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 23°C + 273.15 = 296 K
Step 3: Calculate the moles (n) of oxygen
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol
Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen
The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.
m = n × M
m = 24.7 mol × 32.00 g/mol = 790 g
Answer:
1/2 ( the two answers given are not FRACTIONS)
Explanation:
Moles of CH3OH = 128 gm / 32 gm / mole = 4 moles
Moles of water 72 gm / 18 gm /mole = 4
Mole fraction of CH3OH = 4 / ( 4+4) = 4/8 = 1/2
