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Lesechka [4]
4 years ago
15

At least 100 students at a certain high school study Japanese. If 4 percent of the students at the school who study French also

study Japanese, do more students at the school study French than Japanese?
(1) 16 students at the school study both French and Japanese.
(2) 10 percent of the students at the school who study Japanese also study French.
Mathematics
1 answer:
oksano4ka [1.4K]4 years ago
7 0

Answer: Yes, Number of students who study French is greater than number of students who study Japanese.

Step-by-step explanation:

Since we have given that

Number of high school students study Japanese  ≥ 100

Percent of high school students who study French also study Japanese = 4%

If the Percent of the students who Japanese also study French = 10%

So, our equation becomes

0.04\times F=0.10\times J\\\\\dfrac{F}{J}=\dfrac{0.10}{0.04}=\dfrac{10}{4}

With the help of ratio, we get that

Number of students who study French is greater than number of students who study Japanese.

Hence, Yes, Number of students who study French is greater than number of students who study Japanese.

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When we toss a coin, there are two possible outcomes: a head or a tail. Suppose that we toss a coin 100 times. Estimate the appr
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When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

100 tosses, so n = 100

Two outcomes, both equally as likely. So p = \frac{1}{2} = 0.5

So

E(X) = np = 100*0.5 = 50

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.5*0.5} = 5

Estimate the approximate probability that the number of tails is between 40 and 60.

Using continuity correction.

P(40 - 0.5 \leq X \leq 60 + 0.5) = P(39.5 \leq X \leq 60.5)

This is the pvalue of Z when X = 60.5 subtracted by the pvalue of Z when X = 39.5. So

X = 60.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{60.5 - 50}{5}

Z = 2.1

Z = 2.1 has a pvalue of 0.9821

X = 39.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.5 - 50}{5}

Z = -2.1

Z = -2.1 has a pvalue of 0.0179

0.9821 - 0.0179 = 0.9642

96.42% probability that the number of tails is between 40 and 60.

8 0
3 years ago
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