Need help: write the expression in a complete factored form: x²-9x+xy-9y

1 answer:

4 0

Factor this by grouping. Group the first two terms together and then the second 2 terms together. The idea here is that, after grouping, what you can pull out in both groups is the same. Like this:
$( x^{2} -9x)+(xy-9y)$
Now work on finding a common thing between the 2 groups:
$x(x-9)+y(x-9)$
See, what you have in common there now is the (x-9) that you can factor out:
$(x-9)(x+y)$
And that is factored completely.

You might be interested in

What is the solution of (3x + 8)/(x - 4) >= 02

ipn [44]

Answer:

3x+8=0

x=-8/3The face of the denominator must be 0

And the face and denominator of the fraction must be positive

Step-by-step explanation:

4 0

3 years ago

How do you round 38.25

solniwko [45]

Because its under 6 you must round it down to 38.20 if it was 38.68 for example it would be 38.70

4 0

3 years ago

Read 2 more answers

What are the intercepts of the equation 4x+6y+2z=12?

Bond [772]

Answer:

The answer is D

6 0

3 years ago

Read 2 more answers

How many extraneous solutions does the equation below have?

aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S.

The given equation consisting of variable , m is

$\frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})$