Answer:
Resultant amplitude is 0.53 m.
Explanation:
Amplitude is defined as the maximum displacement of wave particles from their respective mean positions.
The resulting amplitude of any two waves is given by the relation :
A =
Here, A is resultant amplitude, A₁ and A₂ are the amplitudes of two waves respectively and x is the difference in phase angle of the two waves.
According to the problem, A₁ is 0.4 m , A₂ is 0.23 m and x is zero. So, the above equation becomes,
A =
A =
A = 0.63 m
The second choice on the list (#2 or B) is the correct one.
To solve this problem it is necessary to apply the concepts related to internal torque, shear stress and the angle generated from the modulo of elasticity, torque, length and polar moment of inertia.
We will start by finding the angular velocity in units that allow us to find the total torque:
From the indicated variable of power, in English system this would be
With the power and angular velocity found, the torque would then be:
The torsion formula will allow us to find maximum stress due to the shear force acting on the body:
And finally the angle of twist
Therefore the anle of twist in the shaft at full power is 4.58°
Answer:
(a)
(b)
Explanation:
For Part (a)
Given data
The box moves up at steady 5.0 m/s
The mas of box is 50 kg
As ∑Fy=T₁ - mg=0
For Part(b)
Given data
As ∑Fy=T₂ - mg=ma
I believe the answer is the second one.