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antoniya [11.8K]

4 years ago

13

PLEASE HELPPP for BRAINLEIST ANSWER

1 answer:

11111nata11111 [884]4 years ago

6 0

The second choice on the list (#2 or B) is the correct one.

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A sinusoidal wave travels along a string. if the time for a particular point to move from maximum displacement to zero displacem

Lisa [10]

The time it takes for a point to reach 0 displacement from maximum displacement is $\frac{\pi}{2}$ of a cycle. Thus, one period ( $2\pi$ ) will take $T=0.17*4=0.68s$ .

The frequency is simply $f=\frac{1}{T}=\frac{1}{0.68}=1.47Hz$ .

The speed is given by: $v=f\lambda=1.47*1.4 = 2.06m/s$

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3 years ago

Protons have ___charge; they have equal amounts of positive and negative ____charges?

Ray Of Light [21]

Protons have positive charges

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3 years ago

Plzzz HELP MEEEE.

galina1969 [7]

Answer:

D. The state of motion of an object with mass

Explanation:

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7 0

3 years ago

We can model the motion of a bumblebee's wing as simple harmonic motion. A bee beats its wings 250 times per second, and the win

zlopas [31]

Answer:

The amplitude of the wing tip's motion is 1.6 mm.

Explanation:

Given that,

Beat = 250 /s

Speed = 2.5 m/s

We need to calculate the amplitude of the wing tip's motion

Using the equation for the maximum velocity

$v_{max}=2\pi f A$

$A=\dfrac{v}{2\pi f}$

Where,

v = speed

f = frequency

A = amplitude

Put the value into the formula

$A=\dfrac{2.5}{2\pi\times250}$

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$A=1.6\ mm$

Hence, The amplitude of the wing tip's motion is 1.6 mm.

3 0

4 years ago

Read 2 more answers

Find the useful power output (in W) of an elevator motor that lifts a 2600 kg load a height of 30.0 m in 12.0 s, if it also incr

Annette [7]

Answer:

P = 251,916.667 W

Cost = 2,267.25 cents

Explanation:

To solve this question we will use the Work Energy Theorem, which is

$W = dP + dK\\$

Where

$dP$ = Change in Potential Energy

$dK$ = Change in Kinetic Energy

Change in Potential Energy

$P_{i} = mgh_{i}\\ P_{f} = mgh_{f}$

Where

$P_{i}$ = Initial Potential Energy

$P_{f}$ = Final Potential Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$h_{i}$ = Initial Height = 0

$h_{f}$ = Final Height = 30 m

Inputting the values we get the answer for $dP$

$dP = P_{f} - P_{i}\\dP= mgh_{f} - mgh_{i}\\ dP= 10000(9.81)(30) - 0\\ dP= 2943000$

Change in Kinetic Energy

$K_{i} = \frac{1}{2} mv_{i} ^2\\ K_{f} = \frac{1}{2} mv_{f} ^2$

Where

$K_{i}$ = Initial Kinetic Energy

$K_{f}$ = Final Kinetic Energy

$m$ = Mass of System = 10,000 kg

$g$ = Acceleration due to gravity = 9.81 m/s

$v_{i}$ = Initial Velocity = 0 m/2

$v_{f}$ = Final Velocity = 4 m/s

Inputting the values we get the answer for $dK$

$dK = K_{f} - K_{i}\\ dK = \frac{1}{2} mv_{f} ^2 - \frac{1}{2} mv_{i} ^2\\ dK = \frac{1}{2} (10000)(4)^2 - 0 \\ dK = 80000$

Total Work

$W = dP + dK\\$

Inputting the values

$W = 2943000 + 80000$

$W = 3,023,000$

a) Finding the useful Power Output

$P = \frac{W}{t}$

Where

$P$ = Power Output

$W$ = Work Done = 3,023,000J

$t$ = Time = 12s

Inputting the values

$P = \frac{3,023,000}{12}\\ P = 251,916.667$

P = 251,916.667 W

b) Finding the Total Cost

Cost = $0.0900 x P/1000

Cost = $0.0900 x (251,916.667/1000)

Cost = $22.67 or 2,267.25 cents

4 0

4 years ago