We know, F = 1/4πε * q₁q₂ / r²
Here, q₁ = 5 * 10⁻⁶ C
q₂ = 2 * 10⁻⁶ C
r = 3 * 10⁻² m west

Substitute their values,
F = (9 * 10⁹) (5 * 10⁻⁶) (2 * 10⁻⁶) / (3 * 10⁻²)²

F = 100 N [ East of positive charge ]

Hope this helps!

5 0

3 years ago

Read 2 more answers

Iron filings scattered around a magnet will be most strongly drawn toward the _____.

victus00 [196]

<span>The answer is towards <span>the poles. This is because, at the poles of the magnet, the magnetic field lines get closer together hence indicating that the magnetic force is stronger here. The fields are closest together at the center of the magnet and farthest at the outside side of the magnet. </span></span>

8 0

3 years ago

Read 2 more answers

Neglecting air, what speed does a rock thrown straight up have to be to reach the edge of our atmosphere: say 100 km? Still negl

Ugo [173]

To solve this problem it is necessary to apply the kinematic equations of movement description, specifically those that allow us to find speed and acceleration as a function of distance and not time.

Mathematically we have to

$v_f^2-v_i^2 = 2ax$

Where,

$v_{f,i} =$ Final velocity and Initial velocity

a = Acceleration

x = Displacement

From the description given there is no final speed (since it reaches the maximum point) but there is a required initial speed that is contingent on traveling a certain distance under the effects of gravity

$0 - v_i^2 = 2(9.8)(100*10^3)$

$v_i = 14*10^2m/s$

Therefore the speed which must a rock thrown straight up is 14*10^2m/s to reach the edge of our atmosphere.

The displacement and gravity traveled are the same, therefore the final speed will be the same but in the opposite vector direction (towards the earth), that is $14 * 10 ^ 2m / s$

5 0

3 years ago