According to Vieta's Formulas, if
![x_1,x_2](https://tex.z-dn.net/?f=x_1%2Cx_2)
are solutions of a given quadratic equation:
Then:![a(x-x_1)(x-x_2)](https://tex.z-dn.net/?f=a%28x-x_1%29%28x-x_2%29)
is the completely factored form of
![ax^2+bx+c](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc)
.
If choose
![x=d^2](https://tex.z-dn.net/?f=x%3Dd%5E2)
, then:
![\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm \sqrt{64-64} }{2}=4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E2-8x%2B16%3D0%5C%5C%5C%5Cx_%7B1%2C2%7D%3D%20%5Cfrac%7B8%5Cpm%20%20%5Csqrt%7B64-64%7D%20%7D%7B2%7D%3D4%20)
So, according to Vieta's formula, we can get:
![x^2-8x+16=(x-4)(x-4)= (x-4)^2](https://tex.z-dn.net/?f=x%5E2-8x%2B16%3D%28x-4%29%28x-4%29%3D%20%28x-4%29%5E2)
But
![x=d^2](https://tex.z-dn.net/?f=x%3Dd%5E2)
:
Answer:
18
Step-by-step explanation:
basic math :/
Today, I found 1/2 of an old moldy candy bar on the floor under
my desk. I have three co-workers in my office who are all
addicted to chocolate, and none of them can resist free candy.
I loathe and detest all of them, and I see an easy brilliant way
to get at them and their teeth: I'll scrape the fuzz off of the
half-candy-bar, then split it equally among all three of them,
and watch as they chew it and snarf it down.
How much of a complete entire total whole candy bar will I give
to each of these pathetic creatures ?
Answer:
pay rate £7.80
Step-by-step explanation:
28860 divide by 37 = 780
780 divided by 100 = 7.80