When pressing the accelerator on a car, the ___________ energy of the fuel is transformed into the _____________ energy that mak
2 answers:
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Answer:
(a) 5.04 eV (B) 248.14 nm (c)
Explanation:
We have given Wavelength of the light \lambda = 240 nm
According to plank's rule ,energy of light
Maximum KE of emitted electron i= 0.17 eV
Part( A) Using Einstien's equation
, here
is work function.
= 5.21 eV-0.17 eV = 5.04 eV
Part( B) We have to find cutoff wavelength
Part (C) In this part we have to find the cutoff frequency
Answer : Total energy dissipated is 10 J
Explanation :
It is given that,
Time. t = 10 s
Resistance of the resistors, R = 4-ohm
Current, I = 0.5 A
Power used is given by :
Where
E is the energy dissipated.
So, E = P t.............(1)
Since,
So equation (1) becomes :
So, the correct option is (3)
Hence, this is the required solution.