- K.E=18750J
- Mass=m=2100kg
- Velocity=v
QC In ideal flow, a liquid of density 850 kg / m³ moves from a horizontal tube of radius 1.00cm into a second horizontal tube of
1 answer:
The volume flow rates for ∆P is 6.81m³/s .
<h3>What is pressure?</h3>The amount of force applied on perpendicular to the surface of an object per unit area. The unit of it is pascal.
According to bernaulli's theorem theorem
P+1/2pV²+pgy = constant
where p fluid density
g is acceleration due to gravity, pressure at elevation,v is Velocity at elevation ,y is height of elevation.
As there are two tubes then the height of tube 1 is equal to height of tube two .
P1-P2=1/2p(Vd²-Vl²)
The flow rate of liquid is A1V1=A2V2 .
rest is attached in image
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<h3><u>Answer</u> :</h3>
Initial velocity = zero (i.e., free fall)
Final velocity = 30m/s
Acceleration due to gravity = 10m/s²
For a body falling freely under the action of gravity, g is taken positive
◈ <u>First equation of kinenatics</u> :
⇒ v = u + gt
⇒ 30 = 0 + 10t
⇒ t = 30/10
⇒ <u>t = 3s</u>
Hence, object will attain a speed of 30m/s after 3s.