Answer:
C) one-half as great
Explanation:
We can calculate the acceleration of gravity in that planet, using the following kinematic equation:

In this case, the sphere starts from rest, so
. Replacing the given values and solving for g':

The acceleration due to gravity near Earth's surface is
. So, the acceleration due to gravity near the surface of the planet is approximately one-half of the acceleration due to gravity near Earth's surface.
Answer:

Explanation:
given,
width of door dimension = 1 m
mass of door = 15 Kg
mass of bullet = 10 g = 0.001 Kg
speed of bullet = 400 m/s


a) from conservation of angular momentum





256 kPa because p-guage + p-absolute + p-atmospheric = 256
Answer:
1) A trait is a specific feature or characteristic, typically genetic.
2) One trait that helps an animal survive is a Chameleon's camouflage. Camouflage helps the chameleon blend in with their surroundings to avoid a predator or to sneak up on prey.
Explanation: