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2 years ago

Which of the following is correct in order of lowest to highest energy?

2 answers:

5 0

Number three would work because it sarts out with microwaves which is one of the lowest on the cart and ends with gamma rays which is the highest known on the chart

Serggg [28]2 years ago

3 0

It is number 3. Because microwaves are the lowest of the sepectum then visible light the the highest of them all is Gamma Ray's. Hope this helps!!

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A stone is dropped off a cliff. After this stone has traveled a distance d . A second stone is dropped. the distance between the

Sladkaya [172]

Answer:

the same stones distance will be condtant .

so option no E

7 0

2 years ago

A plece of titanium has a mass of 67.5g and a volume of 15cm<br> What is the density?

sveta [45]

Answer:

4.5g/cm^3

Explanation:

Here, Mass(m)=67.5g

Volume(v)=15cm^3

Now, According to formula,

Density(p)=m/v

=67.5/15

=4.5g/cm^3

8 0

2 years ago

Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assu

Elenna [48]

Answer:

Explanation:

The relation between time period of moon in the orbit around a planet can be given by the following relation .

T² = 4 π² R³ / GM

G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .

Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)² = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )

M = .06424 x 10²⁵

= 6.4 x 10²³ kg .

4 0

2 years ago

Directions: Read each question carefully and answer

Lady bird [3.3K]

I have all the answers here so take this

8 0

1 year ago

Consider two wheels with fixed hubs. The hub cannot move, but the wheel can rotate about it. The hubs are fixed to a stationary

kykrilka [37]

Answer:

Magnitude of force on wheel B is 4 N

Explanation:

Given that

$I=mr^2$

For wheel A

m= 1 kg

d= 1 m,r= 0.5 m

F=1 N

We know that

T= F x r

T=1 x 0.5 N.m

T= 0.5 N.m

T= I α

Where I is the moment of inertia and α is the angular acceleration

$I_A=1 \times 0.5^2\ kg.m^2$

$I_A=0.25\ kg.m^2$

T= I α

0.5= 0.25 α

$\alpha = 2\ rad/s^2$

For Wheel B

m= 1 kg

d= 2 m,r=1 m

$I_B=1 \times 1^2\ kg.m^2$

$I_B=1 \ kg.m^2$

Given that angular acceleration is same for both the wheel

$\alpha = 2\ rad/s^2$

T= I α

T= 1 x 2

T= 2 N.m

Lets force on wheel is F then

T = F x r

2 = F x 1

So F= 2 N

Magnitude of force on wheel B is 2 N

3 0

3 years ago