Answer:
0.78m/s
Explanation:
We are given that
Acceleration=
v=0, s=1 when t=0
We have to find the particle's velocity at s=2m
We know that




By using formula:

Substitute s=2




Hence, the velocity of particle at s=2m=0.78m/s
Answer:
work done=fdcosø
f=mg=450N
d=+3m
ø=180
450×3×cos(180°) power=work done/
time taken
1350×-1 p=135watts
Answer:
7 m/s^2
Explanation:
Given that the jet is traveling 37.6 m/s when the pilot receives the message.
And it takes the pilot 5.37 s to bring the plane to a halt.
Acceleration of the plane can be calculated by using first equation of motion
V = U - at
Since the plane is going to stop, the final velocity V = zero.
And the acceleration will be negative
Substitute all the parameters into the formula
0 = 37.6 - 5.37a
5.37a = 37.6
Make a the subject of formula
a = 37.6 / 5.37
a = 7.0 m/s^2
Therefore, the acceleration of the plane to bring the plane to a halt is 7 m/s^2
You would have to put the number together
Answer:
It cannot be constant because if it does not change and each time it increases its strength and speed.
Explanation: