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salantis [7]
3 years ago
7

A box is 5 cm high, 4 cm wide, and 9 cm long. What is the

Physics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

18

Explanation:

  1. 5+4=9+9=<em>18</em><em> </em><em>IS</em><em> </em><em>THE</em><em> </em><em>VOLUME</em><em> </em><em>OF</em><em> </em><em>CUBIC</em><em> </em><em>CENTIMETRES</em><em> </em>
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What question was asked by Faraday that the narrator calls a leap
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<span> If electricity and magnetism can create motion, can the reverse be true? Can motion and magnetism create electricity?</span>
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Could someone summarize these into a paragraph? i'll give brainliest<br> DUE TODAY!!
slamgirl [31]

Answer:

I can't see the picture

Explanation:

Im sorry can you right whats on the picture down in the comments plz.

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In the drawing, water flows from a wide section of a pipe to a narrow section. In which part of the pipe is the volume flow rate
guapka [62]

Answer:

Volume flow rate is the same in both sections of the pipe

Explanation:

7 0
3 years ago
A sled travels 15 meters down a slope inclined at 30 degrees with a horizontal. What is the horizontal displacement of the sled?
Arte-miy333 [17]

Length of the slope is given as

L = 15 m

also the inclination is given as

\theta = 30 degree

now the horizontal displacement is let say "x"

now from geometry we can say

\frac{x}{L} = cos30

x = L cos30

now substitute all values in it

x = 15 * cos30

x = 12.99 m

<em>so it will displace horizontally by 12.99 m</em>

6 0
3 years ago
330 grams of boiling water (temperature 100°C, specific heat capacity 4.2 J/K/gram) are poured into an aluminum pan whose mass i
Alexus [3.1K]

Answer:

T = 74°C

Explanation:

Given Mw = mass of water = 330g, Ma = mass of aluminium = 840g

Cw = 4.2gJ/g°C = specific heat capacity of water and Ca = 0.9J/g°C = specific heat capacity of aluminium

Initial temperature of water = 100°C.

Initial temperature of aluminium = 29°C

When the boiling water is poured into the aluminum pan, heat is exchanged and after a short time the water and aluminum pan both come to thermal equilibrium at a common temperature T.

Heat lost by water equal to the heat gained by aluminium pan.

Mw × Cw×(100 –T) = Ma × Ca × (T–29)

330×4.2×(100– T) = 890×0.9×(T–29)

1386(100 – T) = 801(T –29)

1386/801(100 – T) = T – 29

1.73(100 – T) = T – 29

173 –1.73T = T –29

173+29 = T + 1.73T

202 = 2.73T

T = 202/2.73

T = 74°C

6 0
3 years ago
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