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3 years ago

A box is 5 cm high, 4 cm wide, and 9 cm long. What is the

Physics

1 answer:

FromTheMoon [43]3 years ago

6 0

Answer:

Explanation:

5+4=9+9=18 IS THE VOLUME OF CUBIC CENTIMETRES

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A parallel-plate capacitor is made from two aluminum-foil sheets, each 5.9 cm wide and 5.6 m long. Between the sheets is a Teflo

Zarrin [17]

Answer:

1.98 x 10⁻⁷ F

Explanation:

w = width of the sheet = 5.9 cm = 0.059 m

L = length of the sheet = 5.6 m

Area of the sheet is given as

A = L w = (5.6) (0.059) = 0.3304 m²

d = distance between the sheets = 3.1 x 10⁻⁵ m

k = dielectric constant of teflon = 2.1

Capacitance is given as

$C = \frac{k\epsilon _{o}A}{d}$

$C = \frac{(2.1)(8.85\times 10^{-12})(0.3304)}{3.1\times 10^{-5}}$

C = 1.98 x 10⁻⁷ F

5 0

3 years ago

What's the formula to calculate the radius of pendulum bob

Svetradugi [14.3K]

Answer:

The combination, L = I / (m * R) , that appears in the equation for the period of a physical pendulum, is called radius of oscillations

Hope this helps :]

7 0

3 years ago

A stone is thrown at an angle of 30 degrees above the horizontal from the top edge of a cliff with an initial speed of 12 m/s. A

natta225 [31]

v = initial velocity of launch of the stone = 12 m/s

θ = angle of the velocity from the horizontal = 30

Consider the motion of the stone along the vertical direction taking upward direction as positive and down direction as negative.

v₀ = initial velocity along vertical direction = v Sinθ = 12 Sin30 = 6 m/s

a = acceleration of the stone = - 9.8 m/s²

t = time of travel = 4.8 s

Y = vertical displacement of stone = vertical height of the cliff = ?

using the kinematics equation

Y = v₀ t + (0.5) a t²

inserting the values

Y = 6 (4.8) + (0.5) (- 9.8) (4.8)²

Y = - 84.1 m

hence the height of the cliff comes out to be 84.1 m

5 0

3 years ago

The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s.

marin [14]

The acceleration of the particle at 3s is [tex]a = 6 \beta [/tex]

$v = \alpha + \beta {t}^{2}$

<h3>How to calculate acceleration </h3>

$a = \frac{dv}{dt} \\ v = \alpha + \beta {t}^{2} \\ \frac{dv}{dt} = 0 + 2 \beta t \\$

if Time is given as 3s

therefore, Acceleration is

$a = 2 \beta t \\ a = 2 \beta 3 \\ a = 2 \times \beta \times 3 \\ a = 6 \beta$

Acceleration is

$a = 6 \beta$

Read more about velocity:

brainly.com/question/19365526

6 0

2 years ago

A solid 200-g block of lead and a solid 200-g block of copper are completely submerged in an aquarium filled with water. Each bl

finlep [7]

Answer:

B. The buoyant force on the copper block is greater than the buoyant force on the lead block.

Explanation:

Given;

mass of lead block, m₁ = 200 g = 0.2 kg

mass of copper block, m₂ = 200 g = 0.2 kg

density of water, ρ = 1 g/cm³

density of lead block, ρ₁ = 11.34 g/cm³

density of copper block, ρ₂ = 8.96 g/cm³

The buoyant force on each block is calculated as;

$F_B = mg(\frac{density \ of \ fluid}{density \ of \ object} )$

The buoyant force of lead block;

$F_{lead} = 0.2*9.8(\frac{1}{11.34} )\\\\F_{lead} = 0.173 \ N$

The buoyant force of copper block

$F_{copper} = 0.2*9.8(\frac{1}{8.96})\\\\F_{copper} = 0.219 \ N$

Therefore, the buoyant force on the copper block is greater than the buoyant force on the lead block

3 0

3 years ago