Periodic time is the time taken for one complete oscillation by a body in circular motion. In this case the merry-go round takes 2 minutes to cover 15 complete oscillations. 2 Minutes = 120 seconds
Hence, 15 oscillations takes 120 secs
thus 1 oscillation takes 120/15 = 8 seconds
therefore the period of the merry-go-round = 8 seconds
Wave speed = (wavelength) x (frequency)
= (4 m) x (2 /sec)
= 8 m/sec
The new period is D) √2 T

<h3>Further explanation</h3>
Let's recall Elastic Potential Energy and Period of Simple Pendulum formula as follows:

where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>


where:
<em>T = period of simple pendulum ( s )</em>
<em>L = length of pendulum ( m )</em>
<em>g = gravitational acceleration ( m/s² )</em>
Let us now tackle the problem!

<u>Given:</u>
initial length of pendulum = L₁ = L
initial mass = M₁ = M
final length of pendulum = L₂ = 2L
final mass = M₂ = 2M
initial period = T₁ = T
<u>Asked:</u>
final period = T₂ = ?
<u>Solution:</u>






<h3>Learn more</h3>

<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity