The answer is A because it has 4 sides
Answer: t = 10
Step-by-step explanation:m
Given that; n₁ = 10, n₂ = 10
ж₁ = 50, ж₂ = 30
Sˣ₁ = 20, Sˣ₂ = 20
Now using TEST STATISTICS
t = (ж₁ - ж₂) / √ ( Sˣ₁/n₁ + Sˣ₂/n₂ )
so we substitute our figures
t = ( 50 - 30 ) / √ ( 20/10 + 20/10 )
t = 20 / √4
t = 10
Answer:
Most Likely C) y = -8x + 75
Step-by-step explanation:
- The scatter plot shows a negative association, so the line of best fit has a negative slope. The eliminates A and B, since their slopes are positive.
- The highest point is (0,75). Because of this, it is safe to assume that would be the best estimate of the y-intercept.
- Out best answer is
3(x-1)^2 +2
This is your answer in vertex form, your h and k values are the vertex. Solving the function by using b/2a, we get that h is 1. ( in the equation 3 is your a, 6 is b and 5 is c.). ( 6/2(3)) = 1. We can then plug in 1 as x into the original equation and get positive 2 ( 3(1)^2 -6(1) +5) = 3-6+5 = 2. This is your vertex. In the function, your a value will always stay the same as this is your shrink or stretch. In this case, a is 3 so it will go outside the parenthesis. Put that all together and you get the function above.
Hope this helps :)
Answer:
The company should use a mean of 12.37 ounces.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation , the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce.
This means that
The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)?
This is , considering that when , Z has a p-value of , so when .
Then
The company should use a mean of 12.37 ounces.