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Tom [10]
3 years ago
10

Imagine you are a Starbucks executive traveling to China from the company’s U.S. headquarters. You are going to Beijing to negot

iate a commercial real estate deal. Based on what you know about high and low context differences between the United States and China, what should you avoid doing?
Multiple Choice:A. discussing non-business-related topicsB. relying on situational cuesC. quickly getting down to businessD. shaking hands after the negotiations are completeE. dressing in formal attire
Business
1 answer:
Oksana_A [137]3 years ago
3 0

The answer would be:

A. discussing non-business-related topics

I hope this helped! If so, please mark brainliest!

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The Outlet needs to raise $3.2 million for an expansion project. The firm wants to raise this money by selling zero coupon bonds
Pani-rosa [81]

Answer:

14,783.33 bonds

Explanation:

Given

Par value FV = $1000

n =20 * 2 =40

R= 7.80/2 = 3.90%

Price per bond:

price per bond :PV = \frac{FV/}{(1+r)^n}

     = \frac{000}{(1+0.039)^{40}}

      = \frac{1000}{4.619786467}

      = 216.46

No. of bonds to be issued = \frac{amount to raise}{ price per bond}

                                           = \frac{3,200,000}{216.46}  

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3 0
4 years ago
A researcher wants to test the order of integration of some time series data. He decides to use the DF test. He estimates a regr
pav-90 [236]

Answer:

a) H0: u = presence of a unit root

   HA: u ≠ presence of a unit root  ( i.e. stationary series )

b) t stat = -0.064

c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis

d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise

Explanation:

<u>a) stating the null and alternative hypothesis</u>

H0: u = presence of a unit root

HA: u ≠ presence of a unit root  ( i.e. stationary series )

<u>b) performing the test </u>

critical value = -2.88

T stat = coefficient / std error

          = -0.02 / 0.31  = -0.064

c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis

d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise

   

5 0
3 years ago
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