Question

Calculate the grams of solute required to make 250 g of 0.10% MgSO4 (m/m).

Answer 1

Answer: The grams of solute required to make 250 g of 0.10% $MgSO_4$ is 0.25 g

Explanation:

To calculate the mass percent of element in a given compound, we use the formula:

$\text{Mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

Given :

Mass of solution = 250 g

Mass percent of solution = 0.10%

Putting in the values:

$0.10=\frac{\text{Mass of solute}}{250g}\times 100$

${\text{Mass of solute}}=0.25g$

Answer 2

Answer:

= 0.25 g MgSO4

Explanation:

0.10% implies that the solution will contain 0.1 g of magnesium sulfate, for every 100 mL of solution.

Therefore;

= 250 g × 0.1 g/100 mL

= 0.25 g MgSO4