6.02 x 1023 atoms weigh out 63.55 grams copper.
No. of Molecules in water = 3.5mole x (6.02 x 10^23) molecules/mole = 2.107 x 10^24 molecules of H2O
Answer:
2NaOH + CO2 -> Na2CO3 + H2O
1) Find the moles of each substance
2) Determine the limitting reagent
∴ Carbon dioxide is limitting as it has a smaller value.
3) multiply the limiting reagent by the mole ratio of unknown over known
n(H2O ) = 0.3976369007 × 1/2
= 0.1988184504 moles
4) Multiply the number of moles by the molar mass of the substance.
m = 0.1988184504 × (1.008 × 2 + 16.00)
= 0.1988184504 × 18.016
= 3.581913202 g
Explanation:
Answer:
structure and function
Explanation:
they are independent and single celled organisms
Answer:
Molarity = 0.202 M
7.36 g/L HCl
Explanation:
KOH + HCl ----> KCl + H2O
1 mol 1 mol
0.560mol/L *0.045L x mol/L*0.125L
0.560mol/L *0.045L = x mol/L*0.125L
x = 0.560mol/L *0.045L /0.125L= 0.2016 mol/L≈ 0.202 mol/L=0.202M HCl
M(HCl) = 1.0+35.5 = 36.5 g/mol
0.2016 mol/L*36.5 g/mol ≈ 7.36 g/L HCl
Answer:
210.15 g
Explanation:
The molar mass of nitrogen is approximately 14.01 g/mol.
14.01*15=210.15