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Harman [31]
3 years ago
6

Another name for Group is...

Chemistry
1 answer:
kobusy [5.1K]3 years ago
7 0

Answer:

set, variety, family, species,

Explanation:

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Lauren has a big social studies test coming up. She knows that she needs to spread out her study sessions over a period of time.
tatuchka [14]

The study strategy Lauren is using in spreading her study sessions over a period of time is pacing, which helps the student develop a schedule focused on their own study pace.

<h3>Pacing Study Sessions</h3>

This study strategy of distributing the study into short sessions rather than studying the entire content through one long session is more effective in retaining content and learning.

What happens is that Lauren is using mass repetition processing, which can be compared to a longitudinal wave in physics, with spaces in between, concentrating the initial review close to the proof to ensure retention and avoid forgetting.

Through pacing, Lauren achieves greater motivation to carry out her studies in a concentrated and focused way, helping her to retain and preserve knowledge.

The correct answer is:

  • Pacing

Find out more information about pacing here:

brainly.com/question/988371

5 0
2 years ago
A sample of gas contains 6.25 × 10-3 mol in a 500.0 mL flask at 265°C. What is the pressure of the gas in kilopascals? Which var
RideAnS [48]

55.9 kPa; Variables given = volume (V), moles (n), temperature (T)

We must calculate <em>p</em> from <em>V, n</em>, and <em>T</em>, so we use <em>the Ideal Gas Law</em>:

<em>pV = nRT</em>

Solve for <em>p</em>: <em>p = nRT/V</em>

R = 8.314 kPa.L.K^(-1).mol^(-1)

<em>T</em> = (265 + 273.15) K = 538.15 K

<em>V</em> = 500.0 mL = 0.5000 L

∴ <em>p</em> = [6.25 x 10^(-3) mol x 8.314 kPa·L·K^(-1)·mol^(-1) x 538.15 K]/(0.5000 L) = 55.9 kPa

4 0
3 years ago
Read 2 more answers
At what temperature <br> does water boil
Ipatiy [6.2K]
The temperature is a 100
5 0
3 years ago
Read 2 more answers
Name two human actions needed to slow climate change
NeTakaya

Burning less fossil fuels and riding bikes or walking instead of cars.

Explanation:

7 0
3 years ago
Read 2 more answers
in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,
insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, H_{supplied} = 3.34 × 10³ J

The amount thermal energy gained by the kettle, H_{absorbed}  = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}}  \times 100

Therefore, we get;

\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3}  \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%

The percentage efficiency of the electrical element, η% ≈ 82.186%.

4 0
3 years ago
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