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katen-ka-za [31]
3 years ago
5

Which factor MOST directly affects the flow of ocean currents?w of ocean currents?

Chemistry
1 answer:
Lynna [10]3 years ago
6 0

B)  differences in temperature

Explanation:

The factor that most directly affects the flow of ocean currents is the differences in ocean temperature from one place to another.

Ocean current is the directional movement of the ocean water in its basin.

The main cause of ocean current is differences in temperature.

  • Ocean water on the surface receives direct sunlight.
  • This warms and the surface and decreases their density.
  • When winds blows over them, they cool and sink under their own weight.
  • The less cold water in depths rise to replace them.
  • This exchange of ocean water due to loss and gain of heat cause ocean current.

learn more:

Ocean density brainly.com/question/6760255

#learnwithBrainly

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Pure nitrogen (N2) and pure hydrogen (H2) are fed to a mixer. The product stream has 40.0% mole nitrogen and the balance hydroge
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Explanation:

The given data is as follows.

        Mass flow rate of mixture = 1368 kg/hr

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This means that H_{2} in feed = (100 - 40)% = 60%

We assume that there are 100 total moles/hr of gas (N_{2} + H_{2}) in feed stream.

Hence, calculate the total mass flow rate as follows.

           40 moles/hr of N_{2}/hr (28 g/mol of N_{2}) + 60 moles/hr of H_{2}/hr (2 g/mol of H_{2})

                  40 \times 28 g/hr + 60 \times 2 g/hr    

                  = 1120 g/hr + 120 g/hr

                  = 1240 g/hr

                  = \frac{1240}{1000}              (as 1 kg = 1000 g)

                  = 1.240 kg/hr

Now, we will calculate mol/hr in the actual feed stream as follows.

                 \frac{100 mol/hr}{1.240 kg/hr} \times 1368 kg/hr

                   = 110322.58 moles/hr

It is given that amount of nitrogen present in the feed stream is 40%. Hence, calculate the flow of N_{2} into the reactor as follows.

                       0.4 \times 110322.58 moles/hr

                      = 44129.03 mol/hr

As 1 mole of nitrogen has 28 g/mol of mass or 0.028 kg.

Therefore, calculate the rate flow of N_{2} into the reactor as follows.

                       0.028 kg \times 44129.03 mol/hr

                         = 1235.612 kg/hr

Thus, we can conclude that the the feed rate of pure nitrogen to the mixer is 1235.612 kg/hr.

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