Answer:
324.24 kPa
Explanation:
Given that;
Initial pressure P1 = 101325 Pa
V1= 400 ml
P2 = ?
V2= 125mL
From Boyle's law;
P1V1 = P2V2
P2 = P1V1/V2
P2= 101325 × 400/125
P2= 324.24 kPa
Answer:
the anwser isn't in the choices
Explanation:
H=MC(change of temp.)
M=mass of water=250g
C=specific heat of water = 4.186 j/g
change in temperature is 121-40= 81
H= 250x4.186x81=84766.5J
Answer:
Explanation:
I'm not sure what is being asked, not the units of "1.5." I don't know of potassium "ioxicide." Was "dioxide" intended?
I'll assume the question is "What is the concentration, in Molar, of 1.5g of potassium dioxide in 150cm^3 of water (150cm^3 is 150 ml).
The molar mass of K2O, potassium dioxide, is 94.2 g/mole. 1.5g is (1.5g/94.2 g/mole) or 0.0159 moles of K2O. The definition of Molar is moles/liter. So take the moles of K2O and divide by the liters, which is 0.150L in this case.
(0.0159 moles K2)/0.150 L = 0.106 M K2O
Answer: Below (=
Explanation:
The properties of a compound depend not only on which atoms the compound contains, but also on how the atoms are arranged. Atoms of carbon and hydrogen, for example, can combine to form many thousands of different compounds.