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3 years ago

What is antifreeze used for?

2 answers:

5 0

<span>An antifreeze is an additive which lowers the freezing point of a water-based liquid. An antifreeze mixture isused to achieve freezing-point depression for cold environments and also achieves boiling-point elevation to allow higher coolant temperature.</span>

SashulF [63]3 years ago

3 0

Antifreeze is used to get to freezing-point in cold environments and also boiling-point elevation for coolant temp.

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Convert 9.35•10^24 Nitrogen molecules to moles

Katyanochek1 [597]

Answer:

over the ship

Explanation:

3 0

3 years ago

1. a) Name two examples of good conductors?

Pachacha [2.7K]

A. good conductors - copper, aluminium

b. fair conductors - carbon,human body

c. insulator - paper, wood

7 0

4 years ago

In a neutral atom, the number of protons is always equal to what other part of the atom?

Licemer1 [7]

Answer:

b. The number of electrons

Explanation:

A "neutral atom" has a <u>neutral charge</u>. This means that <em>its charge is equal to </em><em>zero. </em>In order for the charges to cancel out each other, the atom's <em>positive charge should be equal to the negative charge. </em>These being said, the number of electrons<em> (negatively-charged)</em> is then equal to the number of protons <em>(positively-charged). </em>Those atoms which are not neutral are called <em>"ions."</em> This means that they either have more or less electrons than the protons.

7 0

3 years ago

Convert 732.0 mmHg to atm

enot [183]

Answer:

The answer is

Explanation:

To solve the question we use the following conversion

That's

1 mmHg $\cong$ 0.0013 atm

So we have

If 1 mmHg $\cong$ 0.0013 atm

Then 732 mmHg will be

732 × 0.0013 atm

We have the final answer as

Hope this helps you

5 0

4 years ago

A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.

solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

$Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J$

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

$E = \frac{h \times c }{\lambda }$

where,

h: Planck's constant

c: speed of light

$E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J$

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

$\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J$

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

$Ef = \frac{Eo}{Ei} \times 100\% = \frac{1.74J}{130.0J} \times 100\% = 1.34\%$

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

You can learn more about lasers here: brainly.com/question/4869798

8 0

3 years ago