I would say it is a function of all of the choices. if not then the answer is the circulatory system
Answer:it will be c on edg 2021
Explanation:
Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is = ![\frac{8.7}{2.5}KJ](https://tex.z-dn.net/?f=%5Cfrac%7B8.7%7D%7B2.5%7DKJ)
= 3.48 KJ
So, the heat of vaporization ![\delta H_{vap} = 3.48KJ/Mol](https://tex.z-dn.net/?f=%5Cdelta%20H_%7Bvap%7D%20%3D%203.48KJ%2FMol)
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
Answer:
Take E(alpha particle energy) = 5.5 MeV (5.5x106x1.6x10-19)
If the charge on the lead nucleus is +82e(atomic number of lead is 82) = +82x1.6x10-19 C and the charge on the alpha particle is +2e = 2x1.6x10-19 C
Using dc = (1/4πεo)qQ/Eα we have
dc = [9x10^9x(2x1.6x10-19x82x1.6x10-19)]/5.5x10-13 = 6.67x10^-13m. = 6.67 x 10^-13 x 10^15 = 6.67 x 10^2fm
Note: 1meter = 10^15fentometer
Explanation:
This is well inside the atom but some eight nuclear diameters from the centre of the lead nucleus.
Answer:
a) increase exponentially.
Explanation:
The vapor pressure is depend only on temperature.
The vapor pressure of liquid does not depend upon amount of liquid. For example whether the liquid is 50 g or 30 g its vapor pressure will remain same according to the temperature.
The temperature and vapor pressure have exponential relationship. As the temperature of liquid increases its vapor pressure also goes to increase. When the temperature of liquid goes to decrease its vapor pressure also decreases.
The change in vapor pressure of substance when temperature changes is given as,
ln P₂/P₁ = ΔH(va)/R (1/T₁ - 1/T₂)