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mafiozo [28]
3 years ago
6

Compound element ratio of 1:2:6 Ba(NO3)2+Na2SO4

Chemistry
2 answers:
Karo-lina-s [1.5K]3 years ago
5 0

1:2:6? Ba(NO3)2 +Na2SO4 -----> BaSO4 + 2NaNO3

Ba(NO3)2

BaSO4

NaNO 3

Na2SO4

Likurg_2 [28]3 years ago
5 0

Answer:

Ba(NO3)2

Explanation:

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A certain isotope has 53 protons 78 neutrons and 53 electrons. What is its atomic number? What is the mass number of this atom?
statuscvo [17]

Answer:

  1. 53 protons
  2. 131g
  3. Iodine
  4. Halogens

Explanation:

atomic no. = no. of protons

= 53 proton

mass = no. of protons + no. of

neutrons

= 53 + 78

= 131

5 0
3 years ago
What is true of all body except sex cells
Evgesh-ka [11]
They can all by seperrated or replicated.

4 0
3 years ago
H2 is an example of? A. a molecule B. an element or C. both a molecule and an element.
lesya [120]

Answer:

The answer is both molecule and an element

Hydrogen is the chemical element with the symbol H and atomic number 1. ... At standard conditions hydrogen is a gas of diatomic molecules having the formula H2. It is colorless, odorless, non-toxic, and highly combustible.

Explanation:

7 0
2 years ago
The purpose of the salt bridge in an electrochemical cell is to ____.
IgorLugansk [536]

Answer:

A. maintain electrical neutrality in the half-cells via migration of ions

Explanation:

Salt bridge -

For an electrochemical reaction , involving an anode and a cathode , both the electrodes are connect via a salt bridge to complete the circuit for the reaction .

One of the very important use of a salt bridge is to maintain the electrical neutrality of the respective half cells , which is achieved by the movement of ions .

Hence , from the given options , the correct option is ( a ) .

8 0
3 years ago
Mercury chloride is a commercial fungicide. If the molar mass is 470 g/mol and the percent composition is 85.0% Hg and 15.0% Cl,
ElenaW [278]
Data: molar mass 470 g/mol

Percent composition:

Hg = 85.0%
Cl = 15.0%

Solution:

1)  Convert % to molar ratios

A. Base: 100 g

=> Hg = 85.0 g / 200.59 g/mol = 0.4235 mol

     Cl = 15.0 g / 35.45 g/mol = 0.4231 mol

B. divide by the higher number and round to whole number

Hg = 0.4325 / 0.4231 = 1.00

Cl = 0.4231 / 0.4231 = 1.00

=> Empirical formula = Hg Cl

2) Find the mass of the empirical formula:

HgCl: 200.59 g/mol + 35.45 g/mol = 236.04

3) Determine how many times is the empirical mass contained in the molecular mass:

470 g/mol / 236.04 = 1.99 ≈ 2

=> Molecular formula = Hg2 Cl2.

Answers:

Empirical formula HgCl
Molecular Formula Hg2Cl2
6 0
3 years ago
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